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Darya [45]
2 years ago
8

ray is late for work but would like to drink some coffee before he leaves the coffee in the pot is too hot so Ray puts 20 small

cubes in a mug before pouring in the coffee .the ice cubes measure 1 cm per side the mug is cylindrical and has height of 9cm and a base of 7 cm what is volume of the coff3 that will fill the mug after the ice cubes have been added (round to the nearest whole number)
Mathematics
1 answer:
timama [110]2 years ago
4 0

Volume of the mug: PI r^2 (h)

R ====> Radius

H ====> Height

Radius of mug is:

7 / 2 * 1 / 2 b

===> 3.5cm^3

volume of mug:

===> 3.5^2 * PI r^2 * 9

===> 346 cm^3

20 ice cubes ===> 20 cm^3 is needed:

substract:

20 cm^3 - 346

===> 326 cm^3

The volume of the mug is the area of its base; The mug's height, or πr^2 h. This is; 3.5 cm * 3.5 cm. · 9 · π, or 346.2 cm3. The volume of each ice cube is 1 cubic centimeter, so 20 of them will occupy 20 cm^3.

Answer: This leaves 326 cm^3 for the coffee.

Hope that helps!!!! : )

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If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.
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(b) 54.14 m/s

Step-by-step explanation:

The average speed over the given time interval [a,b]: = \frac{y(b)-y(a)}{b-a}

Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t^2.

(a)

(i) average speed = \frac{y(2)-y(1)}{2-1}

=\frac{56(2)-1.86(2)^2-(56(1)-1.86(1)^2)}{1}

=50.42 m/s

(ii) average speed = \frac{y(1.5)-y(1)}{1.5-1}

=\frac{56(1.5)-1.86(1.5)^2-(56(1)-1.86(1)^2)}{0.5}

=51.35m/s

(iii) average speed = \frac{y(1.1)-y(1)}{1.1-1}

=\frac{56(1.1)-1.86(1.1)^2-(56(1)-1.86(1)^2)}{0.1}

=52.094m/s

(iv) average speed = \frac{y(1.01)-y(1)}{1.01-01}

=\frac{56(1.01)-1.86(1.01)^2-(56(1)-1.86(1)^2)}{0.01}

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m/s

(v) average speed = \frac{y(1.001)-y(1)}{1.001-01}

=\frac{56(1.001)-1.86(1.001)^2-(56(1)-1.86(1)^2)}{0.001}

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m/s

(b) y(1)=56(1)-1.86(1)^2

=56-1.86

= 54.14 m/s

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Step-by-step explanation:

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