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wariber [46]
3 years ago
13

Add and Subtract Fractions:

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0
1. 7/10(1/5=2/10)
2. 1/12(1/2=6/12)
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For the quadratic relation y = -3x2 - 7x + 8,
Varvara68 [4.7K]

Answer:

a) y-int is at (0, 8)

b) zeros are at (0.8, 0) and (-3.2, 0); after having rounded to the nearest tenth.

Step-by-step explanation:

Given that y = -3x² - 7x + 8

we can find our y-intercept by setting x = 0

y = -3 (0)² - 7 (0) + 8

y = 8

so, our y intercept is at (8, 0)

To find our zeros, or x-intercepts, we need to set y = 0

0 = -3x² - 7x + 8

Let's use the quadratic formula

x = (-b ± √(b² - 4 (a  * c))) / 2a

where, in this case

a = -3

b = -7

c = 8

x = (7 ± √((-7)² - 4 (-3 * 8))) / (2 * -3)

x = (7 ± √(49 - -96) / -6

x = (7 ± √145) / -6

using the addition pathway

x = (7 + √145) / -6

x = 3.2

using the subtraction pathway

x = (7 - √145) / -6

x = -0.8


So, our x-intercepts, or zeros, will lie on the points

(0.8, 0) and (-3.2, 0)


Create a table of x and y values using the given equation, and plot and graph. Clearly label your y and x intercepts.

(x, y)

(-3, 2)

(-2, 10)

(-1, 12)

(0, 8)

(1, -2)

(2, -18)

(3, -40)

4 0
3 years ago
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