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3 years ago

Please help with this question.

Mathematics

1 answer:

Pavel [41]3 years ago

7 0

The maximum height occurs at the vertex found using t = -b/2a

Solve for t

t = -20 / 2(-5) = -20/-10 = 2 seconds.

Now replace t with 2 in the original equation to solve for the height:

h(t) = -5t^2 + 20t + 110

h(2) = -5(2)^2 + 20(2) +110

h(2) = -5(4) + 40 + 110

h(2) = -20 + 40 + 110

h(2) = 130

Travis only threw the spike 130 meters. Since Laura is at 135 meters, the spike did not reach her.

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4x+2y=18, 5x+4y=13<br> what is the value of x and y

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3 years ago

Anyone know this?? it’s finding the sine of a triangle!!

LenKa [72]

Answer:

I'm not sure what you want me to answer from this, so I solved for every variable:

Angle A: 83°

Side b: 6.29

Side c: 5.8

Step-by-step explanation:

-----Angle A:

Since the sum of the interior angles of a triangle ALWAYS equal 180°, we can solve for angle A as follows:

$A+51+46=180\\A+97=180\\A=83$

-----Side b:

Here, we use the sin rule for finding sides, since we know all of the angles as well as one side:

$\frac{a}{sin(A)} =\frac{b}{sin(B)} \\\frac{8}{sin(83)} =\frac{b}{sin(51)} \\8.06=\frac{b}{0.78} \\6.29=b$

-----Side c:

$\frac{a}{sin(A)} =\frac{c}{sin(C)} \\\frac{8}{sin(83)}=\frac{c}{sin(46)} \\8.06=\frac{c}{0.72} \\5.8=c$

7 0

2 years ago

Read 2 more answers

Laura paddles in her canoe at a speed of 5 mph for 5 miles. She then hops on her windsurfer and sails for 12 miles at a speed of

Inessa05 [86]

Laura paddles in her canoe at a speed of 5 mph for 5 miles.

As we know that

$\text{Distance=Speed*Time}\\ \\ Time=\frac{Distance}{Speed} \\$

Substitute the values we get

$Time=\frac{5m}{5mph}=1hr.......(i)\\$

Laura hops on her windsurfer and sails for 12 miles at a speed of 6 mph.

Again using the above formula we can write

$Time=\frac{12m}{6mph}=2hr.......(ii)\\$

Hence from equation (i) and (ii), we can say total time of travel $=1hr+2hr=3hr\\$

5 0

4 years ago

Read 2 more answers

Si mi disco duro tiene una capacidad de 1.5 Terabytes ¿ cuántas llaves de 32 Gigabits caben en ese disco duro?

Art [367]

Answer:

The number of 32 Gigabit keys that can be fitted on the hard drive is 375.

Step-by-step explanation:

The question is:

If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?

Solution:

1 Terabyte = 8000 Gigabits

Then 1.5 Terabytes in Gigabits is:

1.5 Terabytes = (8000 × 1.5) Gigabits

= 12000 Gigabits

One key is of 32 Gigabits.

Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:

$\text{Number of 32 Gigabit keys}=\frac{12000}{32}=375$

Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.

4 0

3 years ago