We know that AC=8x-20 and B is the mid-point of AC
⇒ AB = BC = 
⇒ BC = 
⇒ BC = 4x-10
Answer:
y+1=-3(x-4)
Step-by-step explanation:
first you want to plug in the numbers into the formula which y-y1=m(x-x1).
then you get y+1=-3(x-4)
Answer:
∠B ≅ ∠F ⇒ proved down
Step-by-step explanation:
<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>
Let us use this fact to solve the question
→ In Δs BCD and FED
∵ ∠C and ∠E are right angles
∴ Δs BCD and FED are right triangles ⇒ (1)
∵ D is the mid-point of CE
→ That means point D divides CE into 2 equal parts CD and ED
∴ CD = ED ⇒ (2) legs
∵ BD and DF are the opposite sides to the right angles
∴ BD and DF are the hypotenuses of the triangles
∵ BD ≅ FD ⇒ (3) hypotenuses
→ From (1), (2), (3), and the fact above
∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency
→ As a result of congruency
∴ BC ≅ FE
∴ ∠BDC ≅ ∠FDE
∴ ∠B ≅ ∠F ⇒ proved
is that x a variable or multiplication symbol?
Step-by-step explanation:
if multiplication the answer is 12 • 10 to the 6th power or 12,000,000 they are the same
Answer: s^2-5s-1/s
Step-by-step explanation: Simplify the expression.
Hope this helps you out! ☺
