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DanielleElmas [232]
3 years ago
7

Please help if right I will give BRAINLIEST and 25 points

Mathematics
1 answer:
Allushta [10]3 years ago
5 0
The total area is 448 in^2. Each triangle is 56 in^2 and each parallelogram is 140 in^2
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. Find the value of $1,300 invested at 4.2% interest compounded continuously for 5 years, 9 months. Round your final answer to t
BARSIC [14]
The formula we use for continuous compounding is A=Pe ^{rt} where P is the initial amount invested, r is the rate as a decimal, and t is time in years.  Our P = 1300, our r = .042, and our t = 5.75 (9 months is 3/4 of a year, and 3/4 in a decimal is .75).  Putting all that into our formula we have A=1300(2.718) ^{(.042)(5.75)}.  We have to multiply those 2 powers together and then raise euler's number to it, then multiply by 1300.  Doing all of that, we get the amount at the end to be $1,655.10
5 0
3 years ago
Is 2 a perfect square ?
wel

Answer:

yes

Step-by-step explanation:

5 0
2 years ago
Factor completely -2x^3 + 6x^2
Bumek [7]

We can factor a -2 and an x^2 out of this using GCF.

<h3><u>-2x^2(x - 3) is what we're left with, and is the fully factored form.</u></h3>
3 0
3 years ago
Given sin thata = 2/5 and 0° &lt; thata &lt; 90°. find sin 2 thata​
Andrej [43]

Recall the double angle identity:

\sin2\theta=2\sin\theta\cos\theta

With \theta measuring between 0º and 90º, we know \cos\theta>0. So from the Pythagorean identity, we get

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\dfrac{\sqrt{21}}5

Then

\sin2\theta=2\dfrac25\dfrac{\sqrt{21}}5=\dfrac{4\sqrt{21}}{25}

5 0
3 years ago
For the following paired data, (1) Calculate the correlation coefficient, r, and (2) at the 0.05 significance level, determine w
expeople1 [14]

Answer:

Linear correlation exists

Step-by-step explanation:

Given the data :

X : | 2 4 5 6

Y : | 6 9 8 10

Using technology to fit the data and obtain the correlation Coefficient of the regression model,

The Correlation Coefficient, r is 0.886

To test if there exists a linear correlation :

Test statistic :

T = r / √(1 - r²) / (n - 2)

n = number of observations

T = 0.886 / √(1 - 0.886²) / (4 - 2)

T = 0.866 / 0.3535845

T = 2.449

Comparing Pvalue with α

If Pvalue < α ; Reject H0

Pvalue = 0.1143

α = 0.05

Pvalue > α ; We reject the null and conclude that linear correlation exists

7 0
3 years ago
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