Find the value of x in each case, please help

You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%

bezimeni [28]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}$

$\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}$

6 0

3 years ago

14. Twelve more than seven times a number equals the number less six

kotegsom [21]

Answer:

The number is -3.

Step-by-step explanation:

Set up an equation:

Variable n = number

12 + 7n = n - 6

Assuming the question is solve for n, isolate the variable:

Subtract n from both sides:

12 + 6n = -6

Subtract 12 from both sides:

6n = -18

Divide by 6 on both sides:

n = -3

Check your work:

12 + 7(-3) = -3 - 6

12 - 21 = -3 - 6

-9 = -9

Correct

3 0

2 years ago

Read 2 more answers

Given that (-3, 5) is on the graph of f(x), find the corresponding point for the function f(x) − 4.

sveticcg [70]

The graph of f(x) - 4 is obtained by translating the graph of f(x) 4 units down.
Therefore, the corresponding point for the function f(x) - 4 is (-3, 5 - 4) = (-3, 1).

7 0

3 years ago

Read 2 more answers

One number is 3 more than another. The product of the number is 54 . Find the numbers.

Mice21 [21]

Answer:

6 and 9

Step-by-step explanation:

set up an equation and solve for x

(x+3) * x = 54

easiest way to to try some numbers.

if you know your multiplication tables...

what two number multiplied together are 54

be sure the numbers you are thinking of meet the rules

is one 3 more than the other

do they multiply together to get 54

6 0

3 years ago

Please calculate this limit <br>please help me

Tasya [4]

Answer:

We want to find:

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}$

Here we can use Stirling's approximation, which says that for large values of n, we get:

$n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n$

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}$

Now we can just simplify this, so we get:

$\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\$

And we can rewrite it as:

$\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}$

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

$\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}$

7 0

3 years ago