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nalin [4]
3 years ago
7

A store manager is looking at past jewelry sales to determine what sizes of rings to keep in stock. The list shows the ring size

s purchased by the last ten jewelry customers.
9, 7, 6.5, 7.5, 7, 8, 5, 6, 7.5, 8
What is the variance of the data set? Round to the nearest hundredths.

0.40
0.72
1.15
2.14
Mathematics
2 answers:
kicyunya [14]3 years ago
7 0

Answer:

1.15 is the answer

Step-by-step explanation:

ss7ja [257]3 years ago
5 0

Answer: 1.15

Step-by-step explanation:

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5, 8, 4<br> LCM: ??????????
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Answer:

40

Step-by-step explanation:

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Is it possible for two different numbers, when squared, to give the same result? What does this result tell you about solving an
Marizza181 [45]
Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
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7 0
3 years ago
True or False. The Electromagnetic Spectrum can be described in terms of wave energy, frequency, and wavelength.
NeTakaya
True, because energy, frequency, and wavelength are all properties of sound, and sound is an electromagnetic wave. The electromagnetic spectrum encompasses a continuous range of frequencies or wavelengths of electromagnetic radiation, ranging from long wavelength, low energy radio waves to short wavelength, high frequency, high energy gamma rays. 
5 0
3 years ago
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

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1 year ago
What is the value of 6x+7y−56x+7y−5 when x = 2 and y = 3?
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