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Feliz [49]
3 years ago
15

Find the volume of a cone that has a radius of 5 yards and a

Mathematics
1 answer:
stepan [7]3 years ago
8 0

Answer:

Volume of the cone = 182.91\,yards^3

Step-by-step explanation:

Radius of the cone = 5\,yards

Height of the cone = 7\,yards

Volume of a cone is:

                 \pi \times r^2 \times\dfrac{h}{3}\\

            =3.14\times (5\times 5)\times \dfrac{7}{3} \\\\=3.14\times 25 \times 2.33\\\\=3.14\times 58.25\\\\=182.905\,yards^3

The Volume of the cone is :182.91\,yards^3

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The are of a rectangle is 259cm2 and its length is 18.5 cm .Find its breath
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For each of these lists of integers, provide a simple formula orrule that generates the terms of an integer sequence that begins
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Answer:

b) next three terms of the sequence are 47, 51, 55

c) The next three terms are 1100, 1101, 1110

d) The next three items in the sequence are therefore, 8,8,8

f) The next three terms are 654729075, 13749310575, 316234143225

g) Therefore the next three items in the sequence are 0,0,0

Step-by-step explanation:

b)7, 11, 15, 19, 23, 27, 31, 35, 39, 43, ...

the common difference, d = T_{2} - T_{1} = 11 - 7 = 4

a_{n} = a_{n-1} + 4

43 + 4 = 47

47 + 4 = 51

51 + 4 = 55

next three terms of the sequence are 47, 51, 55

c)  1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011,...

Each of these terms are binary numbers of 1,2,3,4........

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The second next term  is the 13th term = 1101₂

The third next term is the 14th term = 1110₂

The next three terms are 1100, 1101, 1110

d)  1, 2, 2, 2, 3, 3, 3, 3, 3, 5, 5, 5, 5, 5, 5, 5, ...

1 is repeated 1 time , 2 is repeated 3 times, 3 is repeated 5 times, 5 is repeated 7 times, the next number will sure be repeated 9 times( the repetition follows an odd number pattern)

To know the next number that will be repeated 9 times:

1+2 = 3

2+3 = 5

3 + 5 = 8

The pattern is that the previous summation adds to the preceding number

The next three items in the sequence are therefore, 8,8,8

f)  1, 3, 15, 105, 945, 10395, 135135, 2027025, 34459425,...

The above sequence follows the pattern a_{n} = a_{n-1} (2n -1)\\

The next three terms are the 10th, 11th and 12th terms

a₁₀ = 34459425((2*10)-1)

a₁₀ = 654729075

a₁₁ = 654729075((2*11)-1)

a₁₁ = 13749310575

a₁₂ = 13749310575((2*12)-1)

a₁₂ = 316234143225

The next three terms are 654729075, 13749310575, 316234143225

g) 1, 0, 0, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1,...

The sequence changes between 1 and 0. 6 zeros are expected next

Therefore the next three items in the sequence are 0,0,0

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