Answer:
a. It is a dihybrid cross
b. 0%
c. 0%
d. 0%
e. 100%
f. 0%
g. 0%
Note: Answers are given assuming that hhRD = hhDD
Explanation:
a. The cross, HHdd x hhDD is a dihybrid cross involving two traits: fruit colour and fruit shape
2. Gametes produced in the cross are given below:
for HHdd= Hd and Hd
For hhDD = hD and hD
Offspring produced in the cross:
All HhDd, which represents white and the flattened disc-shaped fruit white since They are both dominant characters.
b. Percentage of the offspring from this cross expected to have the HHDD genotype = 0%
c. Percentage of the offspring from this cros expected to have the hhDD genotype = 0%
d. Percentage of the offspring from this cross expected to have the HhDd genotype = 0%
e. Percentage of the offspring from this cross are expected to produce white and disc-shaped fruits (HHDD or HhDD or HhDd) = 100%
f. Percentage of the offspring from this cross expected to produce white and spherical fruits (HHdd or Hhdd) = 0%
g. Percentage of the offspring from this cross expected to produce yellow and disc-shape (hhDD or hhDd) = 0%
<h3><u>Answer;</u></h3>
Compressions
Rarefactions
<h3><u>Explanations;</u></h3>
- A wave is a transmission of a disturbance from one point to another, and involve the transfer of energy from the source to another point.
- Waves may be classified as longitudinal waves or transverse wave depending on the vibration of particles relative to the wave motion or mechanical and electromagnetic waves based on the material medium of transmission.
- <em><u>Sound waves are examples of longitudinal waves that are mechanical waves since they require material medium for transmission. Longitudinal waves involves transmission of waves such that the vibration of particles is parallel to the wave motion , creating compressions and rarefactions.</u></em>
Your answer is going to be homozygous , the answer is C
Planarian<span>, </span><span>any of a group of widely distributed, mostly free-living flatworms of the class Turbellaria
These are elongated and ciliated
Mouth is middle of the body
hope it helps</span>
This is a question regarding how enzymes increase the rates of reactions. There are choices and the instructions is to check all that apply.
<span>1. They shift the reaction equilibrium towards the products. </span>
<span>2. They increase the concentration of the reactants. </span>
<span>3. They lower the activation energy of the reaction. </span>
<span>4. They decrease the free energy of a reaction. </span>
<span>5. They promote the formation of a transition state.
The correct answers in this question are "they lower the activation energy of the reaction" and "they promote the formation of a transition state". Enzymes do not necessarily shift the the reaction equilibrium to the products, as there are reversible enzymatic reactions that can reverse the pathway back to the substrates. They do not increase the concentration of the reactants as the concentration of the reactants is an independent variable in this process. They do not decrease the free energy of activation as this is a constant in every reaction depending on the substrates and the products.
Enzymes do, however, lower the activation energy of the reaction meaning it will take less energy and effort for the substrates to reach the activation energy to transform it to its transition state then to the products. With this said, enzymes promote the formation of a transition state.
Attached is a simplified image on how enzymes work. </span>