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3 years ago

14

Which of the following is one of the ending compounds during cellular respiration? A.Glucose B.Mitochondria C.Oxygen D.Water

2 answers:

katrin2010 [14]3 years ago

6 0

The ending compound is water

Dominik [7]3 years ago

3 0

It is water............

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What is shown by the pattern of iron filings around these two magnets?

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Answer:c

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3 years ago

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What do electric power companies deliver to customers

kvv77 [185]

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Power plants generate electricity that is delivered to customers through transmission and distribution power lines. High-voltage transmission lines, such as those that hang between tall metal towers, carry electricity over long distances to meet customer needs.

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8 0

3 years ago

To protect their young in the nest, peregrine falcons will fly into birds of prey (such as ravens) at high speed. In one such ep

I am Lyosha [343]

Answer:

Part a)

$\theta = 48 degree$

Part b)

$v = 13.45 m/s$

Explanation:

Part a)

mass of the Falcon bird is given as

$m = 600 g$

initial speed of the bird is

$v_i = 20 m/s$

final speed of the bird is given as

$v_f = 5 m/s$ (opposite direction)

So here the impulse given by falcon bird is given as

$I = m(v_f - v_i)$

$I = 0.600(20 + 5)$

$I = 15 kg m/s$

now the final momentum of Raven bird in perpendicular direction is given as

$I = mv_y$

$15 = 1.50 v_y$

$v_y = 10 m/s$

now the change in the angle of the raven bird is given as

$tan\theta = \frac{v_y}{v_x}$

$tan\theta = \frac{10}{9}$

$\theta = 48 degree$

Part b)

Final speed of the raven bird is given as

$v^2 = v_x^2 + v_y^2$

$v^2 = 9^2 + 10^2$

$v = 13.45 m/s$

5 0

3 years ago

You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo

S_A_V [24]

Answer:

A. Z = 185.87Ω

B. I = 0.16A

C. V = 1mV

D. VL = 68.8V

E. Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

$Z=\sqrt{R^2+\omega^2L^2}$ (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

$Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega$

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

$I=\frac{V}{Z}$ (2)

V: voltage amplitude = 30.0V

$I=\frac{30.0V}{185.87\Omega}=0.16A$

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

$V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV$ (3)

D. The voltage across the inductor is:

$V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V$

E. The phase difference is given by:

$\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°$

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3 years ago

A bags shed and he balls stand slap DC dmss

Natalija [7]

Answer:

is that a question...?

7 0

3 years ago