Answer:
The direction of the car’s change in linear momentum is 149.04° West of North
Explanation:
Momentum is defined as the product of mass of a body and its velocity
Momentum = mass × velocity
Change in Momentum = mass × change in velocity
∆P = m∆v
∆P = m(v-u)
Given m = 1500kg
v = 25m/s
u = 15m/s
∆P = 1500(25-15)
∆P = 1500×10
∆P = 15,000kgm/s
Since the car first travels due East i.e +x direction
x = 25m/s
Travelling due south is negative y direction
y = -15m/s
Direction of the car change
θ = tan^-1(y/x)
θ = tan^-1(-15/25)
θ = tan^-1(-0.6)
θ = -30.96°
Since tan is negative in the second quadrant
θ = 180-30.96
θ = 149.04°
The direction of the car’s change in linear momentum is 149.04° West of North
Answer:
the magnitude of the work done by the two blocks is the same.
Explanation:
The work done by block a on block b is given by:

where Fa is the force exerted by block a on block b, and d is the distance they cover.
The work done by block b on block a is given by:

where Fb is the force exerted by block b on block a, and d is still the distance they cover.
For Newton's third law, the force exerted by block a on block b is equal to the force exerted by block b on block a, therefore

and so

Answer:
11.23%
Explanation:
Lets take
Speed of man in still water =u= 1.73 m/s
Speed of flow of water = v=0.52 m/s
When swims in downward direction then speed of man = u + v
When swims in upward direction then speed of man = u - v
Lets time taken by man when he swims in downward direction is
and when he swims in downward direction is
Lets distance is d and it will be remain constant in both the case




Time taken in still water
2 d= t x 1.73
t=1.15 x d sec


total time in current = 0.82 +0.44 d=1.26 d sec
So the percentage time

Percentage time =11.32%
So it will take 11.32% more time as compare to still current.
The independent variable is how steep the slope is