If your water heat has an efficiency of 95 percent, how much energy would it take to heat 45kg of water from 23 C to 60 C. (The
specific heat of water is 4.18 J/g/C.) Please show your work
1 answer:
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We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
where
is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance
In our problem, I=4.00 A and
, so the potential difference is
where
I is the current flowing through it
R is the resistance
In our problem, I=4.00 A and