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ivann1987 [24]
3 years ago
7

Which is the closest to the height of the ball

Mathematics
1 answer:
bogdanovich [222]3 years ago
7 0

Answer:

C

Step-by-step explanation:

substitute 2.1 for 't' in the given equation

h = 113.391

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-5 2/3 + 3 1/4 + -7 1/3
alexgriva [62]
-9.5

I think I might be wrong
7 0
3 years ago
The diameter of a circle is 8 ft. Find the circumferenceto the nearest tenth.
AURORKA [14]

Answer:

25.1 ft

Step-by-step explanation:

To solve for circumference is pretty simple. Just use the equation 2pi r (r=radius, radius is diameter divided by 2).

So essentially, apply to your calculator:

2(3.14)4=25.12

pretty simple! hope this helps!

6 0
3 years ago
The width of the Ochoa Community Pool is 20 feet.The length is twice as long as it’s width.What is the perimeter of the pool?
yan [13]
The perimeter is 120
Hope this helps:)
5 0
3 years ago
Mach the Zodiac to the Months (In order of Zodiac) (NO HELP FROM FRIENDS OR INTERNET)
Sergio [31]

Answer:

Virgo:september-october,

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The figure here shows triangle AOC inscribed in the region cut from the parabola y=x^2 by the line y=a^2. Find the limit of the
aleksandrvk [35]
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =

(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =

= 2a^3 - 2(a^3)/3 = [4/3](a^3)

Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3

ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =

Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
 



3 0
3 years ago
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