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vodomira [7]
3 years ago
11

0.05 is 1/10 of what

Mathematics
1 answer:
Gennadij [26K]3 years ago
4 0

Answer:

.5

Step-by-step explanation:

.5 times 1/10 is .05. move the decimal over!

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Could anybody solve this by any chance? Thanks
Amiraneli [1.4K]

Answer:

y=x÷20x19

Step-by-step explanation:

x÷20=5% then 5%x19=95% basically 5% off

3 0
2 years ago
A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

5 0
3 years ago
Consider the proof.
fiasKO [112]

Answer:

Correct choice is B

Step-by-step explanation:

In step 4 were proved that \triangle ABC\sim\triangle DEC.

By definition, similar triangles have proportional lengths of corresponding sides. To the side AB corresponds side ED, to the side AC corresponds side DC and to the side BC corresponds side EC. Thus,

\dfrac{AC}{DC}=\dfrac{BC}{EC}.

6 0
3 years ago
Read 2 more answers
Mara put down 7.5% on the purchase of her new
sesenic [268]

Answer: $189 000

brainliest or a thank you please :))

goodluck!

6 0
3 years ago
Can someone help me with this please?!?!?
AURORKA [14]

Answer:

with what know question was there

7 0
3 years ago
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