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Dvinal [7]
4 years ago
5

Find the area of the rectangle.

Mathematics
1 answer:
kirill115 [55]4 years ago
4 0

Answer:

40 units²

Step-by-step explanation:

Area of Rectangle: A = lw

Step 1: Define variables

<em>l</em> = 8

<em>w</em> = 5

Step 2: Substitute and evaluate

A = 8(5)

A = 40 u²

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If f(x) = -2[x] + 8, what is f(-1.8)?<br> O 4 <br> O 6<br> O 10<br> O 12
lina2011 [118]

Answer:

12

Step-by-step explanation:

since the function is -2x+8 and you have been told to find f(-1.8) you have to replace -1.8 were there's x in the function.

f(x)=-2x+8

f(-1.8)=-2x+8

=-2(-1.8)+8

=3.6+8

=11.6 round off to 12

I hope this helps

5 0
3 years ago
Calculate the volume of the pyramid shown with measurements a = 3, b = 7, and c = 9.63 units348 units331.5 units330 units3
Yuri [45]

The volume of a pyramid is given by:

V=\frac{1}{3}\cdot A_b\cdot h\text{.}

Where:

• Ab is the area of the base,

,

• h is the height.

In this case, we have:

• a = 3 units,

,

• b = 7 units,

,

• c = 9 units,

,

• Ab = b * c,

,

• h = a = 3 units.

Replacing the data in the formula above, we get:

V=\frac{1}{3}\cdot(b\cdot c)\cdot a=\frac{1}{3}\cdot(7\text{ units}\cdot9\text{ units})\cdot3\text{ units }=63units^3\text{.}

Answer: 63 units³

5 0
1 year ago
ASAP PLEASE
madam [21]

Answer:

he has to pick the phone up 100 more times

6 0
3 years ago
Read 2 more answers
This is going to be hard ok here i go what is 5678,00000 x 4321,0000000
goldenfox [79]

Answer: 2.45346638e+19

Step-by-step explanation:

4 0
3 years ago
For a sample of 35 items from a population for which the standard deviation is 20.5, the sample mean is 458. At the 0.05 level o
Anika [276]

Answer:

Value of test statistics = 2.30

Step-by-step explanation:

We are given that for a sample of 35 items from a population for which the standard deviation is 20.5, the sample mean is 458.

Also, Null Hypothesis, H_0 : \mu = 450

Alternate Hypothesis, H_1 : \mu\neq 450

The test statistics that will be used here is One sample t-test statistics;

              T.S. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean = 458

             s = sample standard deviation = 20.5

            n = sample of items = 35

So, test statistics = \frac{458-450}{\frac{20.5}{\sqrt{35} } } ~ t_3_4

                            = 2.30

Therefore, the value of test statistics is 2.30 .

3 0
3 years ago
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