6 sec can take penny to strike the ground.
Solution:
Given data:
feet
feet
![h(t)=288+48t-16t^2](https://tex.z-dn.net/?f=h%28t%29%3D288%2B48t-16t%5E2)
Re-arrange the terms from greatest degree to smallest degree.
![h(t)=-16t^2+48t+288](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E2%2B48t%2B288)
We can solve it by applying quadratic formula,
![$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Here a = –16, b = 48, c = 288
![$t=\frac{-48\pm \sqrt{48^2-4(-16)(288)}}{2(-16)}](https://tex.z-dn.net/?f=%24t%3D%5Cfrac%7B-48%5Cpm%20%5Csqrt%7B48%5E2-4%28-16%29%28288%29%7D%7D%7B2%28-16%29%7D)
![$t=\frac{-48\pm \sqrt{2304+18432}}{-32}](https://tex.z-dn.net/?f=%24t%3D%5Cfrac%7B-48%5Cpm%20%5Csqrt%7B2304%2B18432%7D%7D%7B-32%7D)
![$t=\frac{-48\pm \sqrt{20736}}{-32}](https://tex.z-dn.net/?f=%24t%3D%5Cfrac%7B-48%5Cpm%20%5Csqrt%7B20736%7D%7D%7B-32%7D)
![$t=\frac{-48\pm144}{-32}](https://tex.z-dn.net/?f=%24t%3D%5Cfrac%7B-48%5Cpm144%7D%7B-32%7D)
Now, write find two t's using plus and minus operation.
![$t=\frac{-48+144}{-32},\ \ t=\frac{-48-144}{-32}](https://tex.z-dn.net/?f=%24t%3D%5Cfrac%7B-48%2B144%7D%7B-32%7D%2C%5C%20%5C%20t%3D%5Cfrac%7B-48-144%7D%7B-32%7D)
![$t=\frac{96}{-32},\ \ t=\frac{-192}{-32}](https://tex.z-dn.net/?f=%24t%3D%5Cfrac%7B96%7D%7B-32%7D%2C%5C%20%5C%20t%3D%5Cfrac%7B-192%7D%7B-32%7D)
t = –3 (or) t = 6
We cannot write time is negative. so neglect t = –3.
Therefore t = 6.
Hence 6 sec can take penny to strike the ground.
A slope of 1/2 means for every two units to the right we move up one.
We have to be careful here because the graphs don't always use the same scale for x and y.
The bottom left uses the same scale and does indeed go two units to the right for every unit up, so that one is the answer.
Answer:
-x + 18
Step-by-step explanation:
just add 16 and 2. this is the furthest it can be simplified
Answer:
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I do y get this but it might be 4