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Alinara [238K]
3 years ago
5

Which of the following data sets is represented by the histogram.

Mathematics
1 answer:
kherson [118]3 years ago
8 0

Answer:

A) (the first data set)

Step-by-step explanation:

It is the only one that has enough numbers to be represented by the histogram

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Solve graphically x+1 is grater than 2x-2
Greeley [361]
You have to solve using the graph as it says solve graphically
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3 years ago
What is the peremeter and area of the photo below, also please show work .
Nuetrik [128]

Answer:

102.849

Step-by-step explanation:

the perimeter of the square is just 4 × 18.

for the semi-circle the perimeter should be R(pi + 2)

so the perimeter of a semi circle is 30.849

add both values for the final answer which is 102.849

3 0
2 years ago
Which triangle is similar to JKL?
Nadusha1986 [10]
So is this just a free answer or?
5 0
3 years ago
I need help on this question ​
nadezda [96]

Answer:

(12.2,-6.4)

Step-by-step explanation:

The results from Desmos are as shown.

The displayed values are (12.294, -6.353)

4 0
3 years ago
6. Find an exact value. (1 point)
vladimir2022 [97]
<span>6 Find an exact value. 
sin 75°
</span>sin(A+B)=sin(A)cos(B)+cos(A)sin<span>(B)
</span>sin(45)=cos(45)=(2^0.5)/2    sin(30)=0.5      cos(30)=(3^0.5)/2
sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.

<span>7. Find an exact value. 
sine of negative eleven pi divided by twelve.

</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)

= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
the answer is the letter c) quantity square root of two minus square root of six divided by four.

<span>8. Write the expression as the sine, cosine, or tangent of an angle. 
sin 9x cos x - cos 9x sin x
</span>

sin(A−B)=sinAcosB−cosAsinB

sin(9x−x)= sin9xcosx−cos9xsinx= sin(8x)

the answer is the letter c) sin 8x

<span>9. Write the expression as the sine, cosine, or tangent of an angle. 
cos 112° cos 45° + sin 112° sin 45°

</span>

cos(A−B)=cosAcosB<span>+sinA</span>sinB

cos(112−45)=cos112cos45<span>+sin112</span>sin45=cos(67)

the answer is the letter d) cos 67°

10. Rewrite with only sin x and cos x.

sin 2x - cos 2x

 

sin2x = 2sinxcosx<span>
cos2x = (cosx)^2 - (sinx)^2 = 2(cosx)^2 -1 = 1- 2(sinx)^2</span>

sin2x- cos2x=2sinxcosx-(1- 2(sinx)^2=2sinxcosx-1+2(sinx)^2

sin2x- cos2x=2sinxcosx-1+2(sinx)^2

<span>the answer is the letter <span>b) 2 sin x cos2x - 1 + 2 sin2x</span></span>
4 0
3 years ago
Read 2 more answers
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