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Stels [109]
3 years ago
9

Angle A measures (2x + 23)°. Angle B is supplementary to angle A and measures (4x + 46)°. Write and solve an equation to find th

e value of x.
Mathematics
2 answers:
sladkih [1.3K]3 years ago
8 0
2x+23+4x+46=180
6x+69=180
6x=180-69
6x=111
x=111/6
x=18.5
KatRina [158]3 years ago
4 0
Supplementary angles add up to 180 degrees.

2x + 23 + 4x + 46 = 180

Combine like terms:

2x + 4x = 6x
23 + 46 = 69

6x + 69 = 180

Subtract 69 to both sides:

6x = 111

Divide 6 to both sides:

x = 18.5
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90.555555555555 repeating
3 0
3 years ago
What multiplies to -48 and adds to 13
Morgarella [4.7K]

Answer:

The formula to solve this would be:

X x Y = 13

There are at least two combinations of two numbers that you can multiply together to get 13.

Step-by-step explanation:

4 0
2 years ago
2. Jill works for Fast Food Inc. and earns $332 per week and is paid bi-weekly. How much is deducted
adoni [48]

Answer:

Social Security: $9.63                                                                                    

Step-by-step explanation:

5 0
3 years ago
Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
3 years ago
Read 2 more answers
A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s
Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

h(t)=-16t^2+32t+128

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

-16t^2+32t+128=0

The above is a quadratic equation. It can be solved by the formula as follows :

t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = -16, b = 32 and c = 128

t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s

Neglecting negative value, the projectile will land after 4 seconds.

4 0
3 years ago
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