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Artist 52 [7]
2 years ago
8

Find the exact length of the third side. 63 60

Mathematics
2 answers:
Archy [21]2 years ago
8 0

Answer:

Question, are you doing pythagorean theromen?

jarptica [38.1K]2 years ago
7 0

Answer:

57

Step-by-step explanation:

By the way there is another formula so I don't know if I am 100% correct. I added 63+60. Then when you get the answer minus it by 180. I hope it helped! :)

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Sheila plans to row across the lake from point A to point B as shown below. to determine how far she will have to row, she has c
larisa [96]

What is supposed to be shown below?

~Lexi

6 0
3 years ago
2^x-4x=0 find the value of x in the equation
ella [17]

9514 1404 393

Answer:

  x ≈ 0.309906932381 or 4

Step-by-step explanation:

There are no algebraic methods of solving a mixed exponential and polynomial equation. The value of x can be found by guessing, or by other means such as trial and error or graphing.

Attached is a graph showing two solutions. x = 4 is the integer solution (2^4 = 4·4). The irrational solution is approximately x ≈ 0.309906932381. That precision is obtained by Newton's method iteration, easily done by a graphing calculator.

3 0
2 years ago
3 less than the quotient of a number y and 4
mr Goodwill [35]

3 less than the quotient of a number y and 4

3       <        y / 4

3    <     y/4

x 4          x 4

12 < y

6 0
2 years ago
van budgets 12 a day for groceries for weekdays and 15 a day for weekends. write an expression in simplest form to show his groc
Ksenya-84 [330]
The budget of Van for groceries for 1 week is:

12 $ (per a weekday) * 5 (weekdays) + 15 $(per a weekend day) *2 (weekend days) = 60$ +30$ = 90$

The budget of Van for w weeks is:

90 $ (per week) * w (weeks) = 90w dollars.


Answer: 90w $
6 0
3 years ago
how much antifreeze 25% antifreeze and 50% antifreeze should be combined to give 40 gallon of 30% antifreeze?​
VARVARA [1.3K]

32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Solution:</u></h3>

From given,

Final mixture is 40 gallon

Let "x" be the gallon of 25 % antifreeze

Then, (40 - x) is the gallon of 50 % antifreeze

Therefore, according to question,

"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Therefore, we frame a equation as:</u></h3>

25 % of x + 50 % of (40 - x) = 30 % of 40

Solve for "x"

\frac{25}{100} \times x + \frac{50}{100} \times (40-x) = \frac{30}{100} \times 40\\\\0.25x + 0.5(40-x) = 12\\\\0.25x + 20 - 0.5x = 12\\\\0.25x - 0.5x = 12 - 20\\\\-0.25x = -8\\\\0.25x = 8\\\\Divide\ both\ sides\ by\ 0.25\\\\x = 32

Thus, 32 gallons of 25 % antifreeze is used

Then, (40 - x) = (40 - 32) = 8

Thus 8 gallons of 50 % antifreeze is used

6 0
3 years ago
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