Answer:
V = 150.72 yd³
Step-by-step explanation:
To find the volume, we will need to use the formula 
To find the base, we will need to use the volume of a circle, which is 
.
If the diameter is 8, the radius is half which is equivalent to 4. Put this into the equation:
A = π4²
A = 16π ≈ 50.24.
Now, use this in the Volume of a Pyramid formula:
V = 1/3 (50.24 ·9)
V = 150.72 yd³
(4/(x+4-2))/x+1
4/(x+2)=x/4+1/2
(x/4+1/2)/x+1
x=-2/5
We can find a formula for nth term of the given sequence as follows:
1, 5, 12, 22, 35
The 1st differences between terms:
4, 7, 10, 13
The 2nd differences :
3, 3, 3
Since it takes two rounds of differences to arrive at a constant difference between terms, the nth term will be a 2nd degree polynomial of the form: 
, where c is a constant. The coefficients a, b, and the constant c can be found.
We can form the following 3 equations with 3 unknowns a, b, c:
Solving for a, b, c, we get:
a = 3/2, b = -1/2, c = 0
Therefore, the nth term of the given sequence is:
![x^ \frac{m}{n}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2
so
![x^ \frac{1}{2}= \sqrt[2]{x^1}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7B1%7D%7B2%7D%3D%20%5Csqrt%5B2%5D%7Bx%5E1%7D%20%20)
times that by 4
4√x
Answer:
Slope = 1/3
Step-by-step explanation:
<em>Step 1: Define general form of equation of line</em>
An equation of a straight line on two-dimensional plane could be represented in form of: y = Mx + b, with M is slope and b is y-intercept
<em>Step 2: Set up the system to solve for slope M of equation of line</em>
That equation passes 2 points, which are represented in form of (x, y), (3, 7) and (6, 8).
Substitute these values of x and y into the original equation in step 1:
7 = 3M + b
8 = 6M + b
<em>Step 3: Solve the system of equations in step 2 for M</em>
Subtract 1st equation from 2nd equation:
8 - 7 = 6M - 3M + b - b
Simplify both sides:
1 = 3M
Divide both sides by 3:
=> M = 1/3
Hope this helps!
:)
