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NARA [144]
3 years ago
12

Kathy was at a cabin for four nights. The outside temperatures for the four nights were: Night One:   −10 °F      Night Two:    

−2 °F       Night Three:   +1°F Night Four:    −4 °F Which temperature was the coldest?
Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0

the highest negative number would be the coldest as it is the furthest away from 0

 so Night One at -10 would be the coldest

nataly862011 [7]3 years ago
6 0

Answer:

-10

Step-by-step explanation:

I take test and get 100

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In rectangle JKLM, JK is equal to 10 feet and MN is equal to 25 feet, find JL.
Snezhnost [94]

we know that

if JKLM is a rectangle

then

diagonals

MK=JL

so

MK=2*MN------> MK=2*25 ft------> MK=50 ft

JL=MK----> JL=50 ft


therefore


the answer is

JL is 50 ft

7 0
3 years ago
One leg of a right triangle is 4 less than the other leg. The square of the hypotenuse of the right triangle is 80. How long are
Hitman42 [59]
I hope this helps you

6 0
3 years ago
What is the value of x and the measure of MNQ
serg [7]

Answer:

3x - 13 +58 = 90, so 3x +45 = 90

Then 3x = 90 - 45 = 45 and x= 45/3 = 15.

m∠MNQ = 3x-13 = 3(15) - 13

                             =  45-13

                             =   32

6 0
3 years ago
I need help. what is the slope?<br> (The bottom one says : (-1, -6)
ch4aika [34]

Answer:

I believe it would be -11/4.

8 0
3 years ago
Read 2 more answers
Consider a deck with 2626 black and 2626 red cards. You draw one card at a time and you can choose either guess on whether it is
gregori [183]

The maximum earning is v(r,b)

Let v(r,b) be the expected value of the game for the player, assuming optimal play, if the remaining deck has r red cards and b black cards.

Then v(r,b) satisfies the recursion

and

The stopping rule is simple: Stop when v(r,b)=0.

To explain the recursion . . .

If r,b>0, and the player elects to play a card, then:

  • The revealed card is red with probability \frac{r}{r+b}, and in that case, the player gets a score of +1, and the new value is V(r-1,b)
  • The revealed card is black with probability \frac{b}{r+b}, and in that case, the player gets a score of −1, and the new value is V(r,b-1)

Thus, if r,b>0, electing to play a card yields the value f(r,b).

But the player always has the option to quit, hence, if r,b>0, we get v(r,b)=max(0,f(r,b)).

Implementing the recursion in Maple, the value of the game is

v(26,26)=41984711742427/15997372030584

v(26,26)  ≈2.624475549

and the optimal stopping strategy is as follows . . .

  • If 24≤b≤26, play while r≥b−5.
  • If 17≤b≤23, play while r≥b−4.
  • If 11≤b≤16, play while r≥b−3.
  • If 6≤b≤10, play while r≥b−2.
  • If 3≤b≤5, play while r≥b−1.
  • If 1≤b≤2, play while r≥b.
  • If b=0, play while r>0.  

So, The maximum earning is v(r,b)

Learn more about PROBABILITY here

brainly.com/question/24756209

#SPJ4

4 0
2 years ago
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