I believe it is A because line segment AC is equal to line segment BD, and AE and BF are also the same
Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
Answer:
The median grade would be 89
Step-by-step explanation:
To find the median, first put the numbers all in ascending order.
79, 80, 86, 92, 95, 96
Now isolate the middle term or terms. Since there is an even amount of numbers, we pick the two in the middle. To find the median, we take an average of those terms.
(86 + 92)/2 = 89
Answer:x=1
Step-by-step explanation: