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aleksklad [387]
3 years ago
5

Circle $O$ is located on the coordinate plane with center at $(2,3)$. One endpoint of a diameter is at $(-1,-1)$. What are the c

oordinates of the other endpoint of this diameter? Express your answer as an ordered pair.
Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

(6,7)

Step-by-step explanation:

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Complete the table for the given rule y=x/4
vichka [17]
Since they only give you the y values in the table, it would be easier if you isolated the x in the rule:

y = x/4

Multiply both sides by 4

4y = x

Now you can simply substitute the y values into the rule to get the x

4(4) = 16

4(2) = 8

4(9) = 36

~~hope this helps~~

4 0
3 years ago
Helppppp i dont know pslßss​
Natali5045456 [20]

Answer:

width=3

Step-by-step explanation:

area=length X width

length=4 X width

=>area=4 X width X width

=>area=(2 X width)^2

=>36=(2 X width)^2

=>6=2 X width

=>width=3

5 0
3 years ago
Read 2 more answers
What is the point-slope form of a line that has a slope of –4 and passes through point (–3, 1)?
svet-max [94.6K]

Answer:

y - 1 = - 4(x + 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 4 and (a, b) = (- 3, 1), thus

y - 1 = - 4(x - (- 3)), that is

y - 1 = - 4(x + 3)

7 0
3 years ago
A parallelogram has a base of length xplus 7 and a height of xplus 2 and has an area of 50 square units. Find the base and heigh
iris [78.8K]

Hello,


(x+7)(x+2)=50\\\Rightarrow\ x^2+9x+14=50\\\Rightarrow\ x^2+9x-36=0\\\Rightarrow\ x^2+12x-3x-36=0\\\Rightarrow\ x(x+12)-3(x+12)=0\\\Rightarrow\ (x+12)(x-3)=0\\\Rightarrow\ x=-12\ or\ x=3\\If \ x=-12\ then\ x+7

7 0
4 years ago
Need help asap please!
Montano1993 [528]

Answer:

  • determinant: -15
  • x = 3; y = 4; z = 1

Step-by-step explanation:

The matrix of coefficients has one row corresponding to each equation. The constants in that row are the coefficients of the variables in the equation. Coefficients are listed in the same order on each row. A missing term is represented by a coefficient of 0.

<h3>coefficient matrix, determinant</h3>

The first attachment shows the coefficient matrix and its determinant.

__

<h3>solution</h3>

The solution to the system of equations can be found by left-multiplying the constant vector by the inverse of the coefficient matrix.

  \textbf{A$\cdot$X}=\textbf{B}\\\\\textbf{X}=\textbf{A}^{-1}\cdot\textbf{B}

This multiplication is shown in the second attachment. It tells us ...

  \textbf{X}=\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}3\\4\\1\end{array}\right]

4 0
2 years ago
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