The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
OBAN
92
|
| STANRAER
172-------------------------------------112
To read this table you have to draw a vertical from OBAN downward aa horizontal line from the 1st value of STANRAER. The intersection point show the number of miles.
So there are 172 miles & the consumption is 8 mi/gal,. He needs 172/8 gal.
Cost number of gallons needed x price/ gallon
COST = (172/8) x 0.83
COST = (21.5) x 0.83 = 17.845 ≈ $17.85 (1st answer)
Showing fractions can be expressed in model and number line.
Using a model, you have to draw the number of parts (denominator) and shade the number of parts (numerator).
Using a number line, the line starts from 0 to the number of the denominator. You put a marker to the number that is the same as the numerator.
Both model and number line use the value of the numerator and denominator. What makes them different is how they are presented. Model can easily be understood compared to number line.
Answer:
x=24
Step-by-step explanation:
The Quotient(dividing) of a number(x) and 6 minus(-) 3 IS(=) 1.
Which turns into:
- 3 = 1
We want to get x by itself so we divide the entire equation by 6.
6 (
- 3 = 1 )
x - 18 = 6
We want to move the plain numbers to one side so x can be by itself. So we add 18 to both sides.
x = 24