Question

Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).

Answer 1

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Linear equation

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

For RS:

• $Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(4-3)^2+(4-2)^2}=2.24 \\ \\ slope=\frac{y_2-y_1}{x_2-x_1} =\frac{4-3}{4-2}=0.5$

For RT:

• $Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-3)^2+(5-2)^2}=4.24 \\ \\ slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-3}{5-2}=-1$

For ST:

• $Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-4)^2+(5-4)^2}=4.12 \\ \\ slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-4}{5-4}=-4$

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Find out more on linear equation at: brainly.com/question/14323743