Can’t see diagram. Could you attach the photo.
1: incomplete inheritance
2: dominant, recessive
3: polygenic inheritance
4: multiple alleles
Answer:
1) In the first step, we need to predict the possible alleles for the cross. The dominant allele will be written with a capital letter. The recessive allele will be written with a small letter. Hence, the allele for brown hair colour will be B and the allele for red hair colour will be b.
2) In the second step, we need to determine the genotype of the parents. The genotype of the homozygous dominant parent will be BB. The genotype of the heterozygous brown hair colour will be Bb.
3) The punnet square for cross between these parents can be shown as follows:
B b
B BB Bb
B BB Bb
4) In the fourth step, lets determine the phenotype of the children. The phenotype of all the offsprings born will be brown hair colour.
5) The genotype from the punnet square shows that there is a 50% chance that the offsprings will be heterozygous dominant (Bb) for brown hair colour and their will be a 50% chance that the child born will be homozygous dominant (BB).
Answer:
The genotype of both parents is RrYy.
The possible types of gametes would be RY, Ry, rY, and ry.
The cross would produce offspring that can have one out of four types of phenotypes:
- Round and yellow seeds (1 RRYY+ 2 RrYY +2 RRYy + 4 RrYy) = 9/16
- Wrinkled and yellow seeds (3 rrYy) = 3/16
- Round and green seeds (1 RRyy + 2 Rryy) = 3/16
- Wrinkled and green seeds (rryy) = 1/16
Thus, one out of 16 offspring would have wrinkled and green seeds.
