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chubhunter [2.5K]
3 years ago
11

Pls Help Me

Biology
2 answers:
Alex Ar [27]3 years ago
7 0

The answer is False. Because plants have to adapt to drought.


zmey [24]3 years ago
6 0
Thats false because a plant can adapt too lack of water or temperature
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A heterozygous tall pea plant is allowed to self-fertilize. The resulting F1 progeny are 25% homozygous tall, 50% heterozygous t
maks197457 [2]

Answer:

25% heterozygous tall

Explanation:

If we take the F1 generation as parents and let them self-fertilise, we have 4 crosses.

The first one for homozygous tall, then we have 100% AA.

The second and third one for heterozygous tall and we have 25% AA, 50%Aa and 25%aa for each of them.

The last one would be for dwarf, and we'll have 100%aa.

Adding all of them, we'll have

AA = 100 + 25 + 25 = 150%

Aa =  50+50 = 100%

aa = 100 + 25 + 25 = 150%

as we had 4 crosses, so dividing the total percentages by 4, we'll have,

AA = 37.5%

Aa = 25%

aa = 37.5%

:. The percentage of heterozygous tall would be 25%.

Hope it helps:)

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Explain why a person making an emergency call should never be placed on hold
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Round (R) seed shape is dominant to wrinkled (r) seed shape in pea plants. If an RR plant is crossed with an rr plant, what is t
melamori03 [73]

Answer:

The correct answer is b. All round seeds

Explanation:

If an RR plant is crossed with an rr plant than all the phenotype will produce round seed and the frequency of the Round seed plant to wrinkled seed plant would be 4:0.

                       R     R

                  r   Rr    Rr

                  r   Rr    Rr

So all the phenotypes will be heterozygous dominant for the round seed which means that all phenotypes will have a single dominant allele for round seed which is enough to express round seeds in the phenotypes.

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