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3 years ago

6. 5x – 2y = 17 2x + 3y = 3 How do i do elimination on this problem.

Mathematics

1 answer:

kolbaska11 [484]3 years ago

3 0

Answer:

Add the equations in order to solve the first variable. Plug this value into the other equation in order to solve the remaining variables.

The point form is (3,-1)

The equation form is x = 3, y = -1

Hope this helps!

<u><em>PLEASE, </em></u>consideer brainliest. I only have 3 left and then my rank will go up.

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(20 pts)

irakobra [83]

A function can be represented by equations and tables

4 users are logged in by 9am
The domain is [3,23] and the range of the function is [3,4]

<h3>The number of users at 9am</h3>

The function is given as:

$g(x) = \frac14 \sqrt{x - 3} + 3$

At 9am, x = 9.

So, we have:

$g(x) = \frac14 \sqrt{9 - 3} + 3$

$g(x) = \frac14 \sqrt{6} + 3$

Simplify

$g(9) = 3.6$

Approximate

$g(9) = 4$

Hence, 4 users are logged in by 9am

<h3>The domain</h3>

Set the radical to 0

$x - 3 = 0$

Solve for x

$x = 3$

The maximum time after midnight is 23 hours.

So, the domain is [3,23]

<h3>The range</h3>

When x = 3, we have:

$g(x) = \frac14 \sqrt{x - 3} + 3$

$g(3) = \frac 14 * \sqrt{3 - 3} + 3 = 3$

When x = 23, we have:

$g(23) = \frac 14 * \sqrt{23 - 3} + 3 = 4$

So, the range of the function is [3,4]

Read more about domain and range at:

brainly.com/question/2264373

3 0

2 years ago

What is the range

Elena-2011 [213]

C I believe the -2 part that was the one just looked it up on google XD hope it helped

7 0

3 years ago

How to solve for z 6-1/2z=2/3

sergey [27]

6 - 1/2z = 2/3
Steps
First, subtract 6 from both sides
6 - 1/2z - 6 = 2/3 - 6
Then, simplify
-1/2z = -16/3
Then, multiply both sides by -2
(-1/2z) (-2) = (-16/3) (-2)
Then, simplify
z = 32/3

3 0

3 years ago

Read 2 more answers

Write this statement in your own words: ∃x ∈ ℕ, y ∈ ℤ|x² = y² Rewrite this using the appropriate mathematical notation: Even num

Serga [27]

Answer:

See below.

Step-by-step explanation:

So we have:

$\exists x\in\mathbb{N},y\in\mathbb{Z}|x^2=y^2$

This can be interpreted as:

"There exists a natural number <em>x</em> and an integer <em>y</em> such that x² is equal to y²."

So we want even numbers are in the set of integers.

$\{2n:n\in\mathbb{Z}\}\in\mathbb{Z}$

This is interpreted as:

"The set of even numbers (2n such that n is an integer) is in the set of integers"

6 0

3 years ago

The arena satisfaction survey was sent out to 650 people. In total 3/5 of people returned the survey. How many people returned t

Angelina_Jolie [31]

This is a proportion problem that involves cross multiplication

3/5 = x/650

650 x 3 = 1950

1950/ 5 =390

Or you could have done 650 x .6 (which is the decimal form of 3/5) and got 390 as your answer

7 0

3 years ago

Read 2 more answers