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ycow [4]
3 years ago
9

PLEASE HELPPPP!!!

Mathematics
1 answer:
Elena L [17]3 years ago
6 0

follow the above steps may be it's right

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Which steps would you use to plot the point (7, −6, −5) in a 3-dimensional coordinate system starting from the origin?
I am Lyosha [343]

Answer:

B. move forward 7, left 6, and down 5

Step-by-step explanation:

By the <u>convention of 3D geometr</u>y, the coordinates of a point (x,y,z) represent how far the point is from the origin forward-backward , right/left , up-down respectively with prior one for the positive coordinate and latter for the negative coordinate.

so we need to move forward 7 for x=7 then to left 6 for y=-6 and then down 5 for z=-5.

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3 years ago
A polygon is shown on the graph:
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so translation means that the points are moving on the graph

so the shape is moving down three then left two

it doesn’t change the shape in any way it just moves the shape

so all the sides and angles are the same

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3 years ago
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When a trend line is drawn on a scatterplot, there are 4 points above the trend line. About how many points should be below the
scoundrel [369]
There is no exact rule for lines of best fit. However, in general, there should be roughly the same amount above as below. So, if we are following this rule, there should be about 4 below as well. 
5 0
2 years ago
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Draw the image of the figure with the given vertices under a dilation with the given scale factor centered at the origin j(-2,2)
Elenna [48]

Answer:

See Attachment.

Step-by-step explanation:

To create the new figure, we must multiply each coordinate by the scale factor, which is 1/2 in this case.

So j(-2,2) becomes j'(-1,1)

K(4,2) becomes K'(2,1)

L(4,-2) becomes L'(2,-1)

and M (-2,-2) becomes M'(-1,-1)

The scale factor is between 1 and 0 which means that this dilation is a reduction that will shrink the original figure to a smaller one.

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2 years ago
Given the diagram, which theorem would you use to find AD?
bagirrra123 [75]

Answer:

B

AD will be 20

<h2 /><h2><em><u>Please</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>brainlie</u></em><em><u>st</u></em></h2>
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