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attashe74 [19]
3 years ago
11

D%20" id="TexFormula1" title=" \frac{3 {w}^{6} {v}^{5} }{15 {w}^{2} v} " alt=" \frac{3 {w}^{6} {v}^{5} }{15 {w}^{2} v} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
ehidna [41]3 years ago
5 0
Breaking down:
\frac{3}{15}  =  \frac{1}{5}
{w}^{6}  \div  {w}^{2}  =  {w}^{4}
{v}^{5}  \div v =  {v}^{4}

Therefore,
\frac{3 {w}^{6} {v}^{5} }{15 {w}^{2}v } \\  =  \frac{{w}^{4} {v}^{4}  }{5}

Hope this helps. - M
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Answer:

View explanation.

Step-by-step explanation:

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3 years ago
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4 years ago
(N^3 - N^4) - (3n^3- 7n^4)
Free_Kalibri [48]
If you would like to solve (n^3 - n^4) - (3n^3 - 7n^4), you can do this using the following steps:

(n^3 - n^4) - (3n^3 - 7n^4) = <span>n^3 - n^4 - 3n^3 + 7n^4 = n^3 - 3n^3 - n^4 + 7n^4 = -2n^3 + 6n^4
</span>
The correct result would be <span>-2n^3 + 6n^4.</span>
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andrew-mc [135]

Answer:

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Step-by-step explanation:

6 0
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