The mean ages with standard deviations of four swim teams at a swim club are given below.

Mathematics

2 answers:

xz_007 [3.2K]4 years ago

7 0

Answer:

Statement 2 (The ages of the Stars are the most dispersed from the team’s mean).

Step-by-step explanation:

Standard deviation is one way to measure the average of the data by determining the spread of the data. It actually explains how much the observation points are further away from the mean of the data. Higher the standard deviation, higher the spread of the data and higher is the uncertainty. This means that the team with the highest standard deviation will have the most dispersion. In this case, the standard deviation of 4.1 is the largest number, therefore, the statement "The ages of the Stars are the most dispersed from the team’s mean." is true i.e. the option 2!!!

Oksanka [162]4 years ago

5 0

Answer:

B.The ages of the Stars are the most dispersed from the team’s mean

Step-by-step explanation:

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When y is 4, p is 0. 5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equatio

dmitriy555 [2]

Answer:

$\dfrac{xy}{pm}=8$

Step-by-step explanation:

If x varies directly as the product of p and m, and inversely with y, the relation can be written ...

x = k(pm)/y . . . . where k is the constant of proportionality

This can be solved for k:

k = xy/pm

For the given values, the value of k is ...

k = (2)(4)/((0.5)(2)) = 8

Then the relation between the variables can be written ...

(xy)/(pm) = 8

5 0

2 years ago

Pleaseeeeeeee help .......ASAP

fenix001 [56]

Answer:

Option A

Step-by-step explanation:

Given:

Center of circle = (h,k)= (3,8)

Radius = r = 5

The standard form of equation of circle with center and radius is:

$(x-h)^2+(y-k)^2=r^2\\Putting\ the\ values\\(x-3)^2+(y-8)^2=(5)^2\\Simplifying\\x^2+9-6x+y^2+64-16y=25\\x^2+y^2-6x-16y+9+64=25\\x^2+y^2-6x-16y+73=25\\x^2+y^2-6x-16y+73-25=0\\x^2+y^2-6x-16y+48=0$