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ch4aika [34]
3 years ago
7

What is the prouduct of 5/6 x 3. show work using the number line method

Mathematics
1 answer:
Rudik [331]3 years ago
5 0
5/6 times 3/1= 15/6 so that will be your answer
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Solve for x<br><br> explain how to do it pls
Arte-miy333 [17]
X=7

(15x+3)=108
x=7

if you plug 7 in for x

(15(7)+3) it equals 108
7 0
3 years ago
A supply company manufactures copy machines. The unit cost C (the cost in dollars to make each copy machine) depends on the numb
Ugo [173]
To answer this item, we take the differential of the equation and equate to zero.
 
                  C(x) = 0.8x² - 256x + 25939

Differentiation,
                dC(x) = 1.6x - 256 
                 dC(x) = 1.6x - 256 = 0

The value of x from the derived equation above is 160. 

Thus, the number of machine to be made in order to minimize the cost should be 160. 
4 0
3 years ago
Read 2 more answers
Cassidy's diving platform is 6 ft above the water. One of her dives can
avanturin [10]

Answer:

Before coming back up to the surface the maximum depth, Cassidy went was 6.25 ft. below the water surface

Step-by-step explanation:

The height of Cassidy's diving platform above the water = 6 ft.

The equation that models her dive is d = x² - 7·x + 6

Where;

d = Her vertical position or distance from the water surface

x = Here horizontal distance from the platform

At Cassidy's maximum depth, we have;

dd/dx = d(x² - 7·x + 6)/dx = 2·x - 7 = 0

x = 7/2 = 3.5

∴ At Cassidy's maximum depth, x = 3.5 ft.

The maximum depth, d_{max} = d(3.5) = 3.5² - 7 × 3.5 + 6 = -6.25

The maximum depth, Cassidy went before coming back up to the surface = d_{max} = -6.25 ft = 6.25 ft. below the surface of the water.

8 0
2 years ago
G(-2)=(-2)^2+3^-2-19
gladu [14]
G=67/9 or in decimal form g=7.4

6 0
3 years ago
If you are given only one length of one side of your right triangle, how do you find the the other side of the triangle? Like if
lidiya [134]

Answer: You apply the trigonometric ratios of Sine, Cosine and Tangent.

Step-by-step explanation: In a question such as this one of the angles must be given, which is labeled the reference angle. We already know one angle is 90 degrees in a right angled triangle, so the other two angles whatever their size is, must both add up to 90, which means they are both acute angles. If one side is given, for instance 10 units, and one of the two acute angles is given, for example 30 degrees, then the line facing the reference angle (30 degrees) would be the OPPOSITE. The line that lies between the angles 30 and 90 would be the ADJACENT while the third side which is the longest would be the HYPOTENUSE.

So if for instance, the opposite line is 10 units, and you are required to calculate the other line, the adjacent, AS LONG AS YOU HAVE BEEN GIVEN A REFERENCE ANGLE, you can simply calculate as follows;

TanX = opposite/adjacent (and that becomes)

Tan 30 = 10/adj

Adj = 10/Tan 30

Adj = 10/0.5774

Adj = 17.32

**Note that the use of angle 30 was just for the sake of explanation. Your reference angle whatever it is, would be provided by your examiner**

5 0
3 years ago
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