Find the measurement of angle X A) 91° C) 1360 B) 1050 D) 100°

In one baseball season, Peter hit twice the difference of the number of home runs Alice hit and 6. Altogether they hit 18 home r

monitta

12 is the answer and everyone hit that season if u think u will see that no offense

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3 years ago

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An airplane is traveling at a speed of 240 miles/hour with a bearing of 110°. The wind velocity is 56 miles/hour at a bearing of

vodka [1.7K]

Answer:

Actual speed = 288 miles per hour

Actual direction angle = $116.38^\circ$

Step-by-step explanation:

"Bearing" is the relative position of an object outside the plane compared to the position of the plane.

Heading the the direction the nose of the plane is pointing.

Course is the direction that pilot wants the plane to go.

Wind direction is always the direction the wind is blowing from.

The airplane is traveling at a speed of 240 miles/hour with a bearing of 110°.

If the plane is traveling with a bearing of 110° and the wind is blown at a bearing of 325°.

$325^{\circ}- 110^{\circ} =225^{\circ}$

$215^{\circ}- 180^{\circ} =35^{\circ}$

The Ground speed will be in excess of the airspeed and true direction will be south if the indicated heading.

The tailwind component is:

$56 cos (35^\circ)$

And the cross wind component is:

$56 sin (35^\circ)$

And that is,

$C^2 = (286)^2 + (32)^2$

$c = 288$

So the actual speed of the plane is 288 miles per hour.

The deviation in the direction is:

Let the direction angle be 'x'.

$x = tan ^{-1}\left ( \frac{32}{286} \right )=6.38^\circ$

So the actual direction angle is $110^\circ+ 6.38^\circ=116.38^\circ$ .

5 0

3 years ago

Consider a t distribution with 7 degrees of freedom. Compute P(-1.29 < t < 1.29). Round your answer to at least three deci

ss7ja [257]

Answer:

a) 0.76197086

b) -1.73406361

Step-by-step explanation:

a)

Consider a t distribution with 7 degrees of freedom. Compute P(-1.29 < t < 1.29)

P(-1.29 < t < 1.29) would be the area under the t distribution curve with 7 degrees of freedom between -1.29 and 1.29, that is in the interval (-1.29, 1.29).

This can be done the old style by looking up in a table or by using the technology with a spreadsheet.

In Excel, the function TDIST(x,n,2) with x>0 gives the area outside the interval (-x, x) of the t distribution with n degrees of freedom.

So TDIST(1.29,7,2) gives the area outside (-1.29, 1.29).

If we subtract this value from 1 we get the desired result

Hence

P(-1.29 < t < 1.29) = 1 - TDIST(1.29,7,2) = 1 - 0.23802914 = 0.76197086

In OpenOffice Calc, the function is the same replacing “,” with “;”

That is

P(-1.29 < t < 1.29) = 1 - TDIST(1.29;7;2) = 0.76197086

b)

Consider a t distribution with 18 degrees of freedom. Find the value of c such that P(t≤ c) = 0.05

We are looking for a point c such that the area of the t distribution with 18 degrees of freedom to the left of c is 0.05

In Excel, the inverse function of TDIST is TINV.

TINV(p*2,n) with p>0 gives the point c such that the area of the t distribution with n degrees of freedom to the right of c is p.

Since the t distribution is symmetric with respect to 0, -c would be a point such that the area to the left of -c is p.

So we want to compute in Excel

-TINV(0.05*2,18) = -1.73406361

In OpenOffice Calc

-TINV(0.05*2;18) = -1.73406361

3 0

3 years ago

What prevent is modeled below

r-ruslan [8.4K]

Answer:

B 35%

Step-by-step explanation:

35/100 reduces to .35. To turn this into a percent, multiply it by 100 and add a percent sign. .35 * 100 = 35. 35%

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4 years ago

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The length of a rectangular frame is 5 cm more than the width. The area inside the frame is 66 square cm. Find the width of the

Ratling [72]

For this case we have that the area is given by:
A = (w) * (l)
Where,
w: width
l: long
Substituting we have:
66 = (w) * (w + 5)
Rewriting
w ^ 2 + 5w - 66 = 0
(w + 11) * (w-6) = 0
Using the positive root we have:
w = 6
Answer:
the width of the frame is:
w = 6 cm

6 0

3 years ago