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mel-nik [20]
3 years ago
9

Answer.com after three half-lives, what fraction of a radioactive sample has decayed?

Chemistry
2 answers:
PSYCHO15rus [73]3 years ago
7 0
<span>After 1 half-life, 1/2 the sample has decayed. After 2 half-lives 3/4 of the matter has decayed. So after, 3 half-lives about 11/12 would have decayed.</span>
vitfil [10]3 years ago
3 0

Answer: Thus the fraction decayed is \frac{7a_o}{8}

Explanation: Radioactive decay follow first order kinetics.

Now, to calculate the amount decayed after n half lives, we use the formula:

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives

a_o = Initial amount of the reactant

n = number of half lives  = 3

Putting values in above equation, we get:

a=\frac{a_0}{2^3}

a=\frac{a_0}{8}

The fraction decayed after 3 half lives will be \frac{1}{8} of the initial amount.

Thus the fraction decayed is a_0-\frac{a_0}{8}=\frac{7a_o}{8}

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Definition of a chemical property
olchik [2.2K]
A chemical property<span> is any of a material's </span>properties<span> that becomes evident during, or after, a </span>chemical<span> reaction; that is, any quality that can be established only by changing a substance's </span>chemical<span> identity.</span>
3 0
3 years ago
The initial reaction rate for the elementary reaction 2A + B → 4C was measured as a function of temperature when the concentrati
Artist 52 [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) The activation energy is 124.776\frac{kJ}{mole}

b) The frequency factor is 1.77 ×10^{18}

c) The rate constant is 0.00033 (\frac{dm^{3} }{mole} )^{2}\frac{1}{s}

Explanation:

From the question the elementary reaction for A and B is given as

      2A + B → 4C

The rate equation the elementary reaction is

      -r_{A} = k[A]^{2}[B]

            =  k[2]^{2}[1.5]

            = 6k

     k = \frac{-r_{A} }{6}

      When temperature changes, the rate constant change an this causes the rate of reaction to change as shown on the second uploaded image.

The relationship between temperature and rate constant can be deduced from these equation

                    k = Aexp(-\frac{E_{a} }{RT} )

             taking ln of both sides we have

                   lnk =ln A - (\frac{E_{a} }{R}) \frac{1}{T}

        Considering the graph for the rate constant ln k and (\frac{1}{T} ) the slope from the equation is -(\frac{E_{a} }{R}) and the intercept is ln A

From the given table we can generate another table using the equation above as shown on the third uploaded image

The graph of ln k  vs (\frac{1}{T} )  is shown on the fourth uploaded image

  From the graph we can see that the slope is -(\frac{E_{a} }{R} ) = - 15008

Now we can obtain the activation energy E_{a} by making it the subject in the equation also generally R which is the gas constant is 8.145 \frac{J}{kmole}

                E_{a}  = 15008 ×  8,3145\frac{J}{molK}  

                     = 124\frac{KJ}{mole}

    Hence the activation energy is = 124\frac{KJ}{mole}

b) From the graph its intercept is ln A = 42.019

                                                          A = exp(42.019)

                                                             =1.77 × 10^{18}

Hence the frquency factor A is  =1.77 × 10^{18}

c) From the equation of rate constant

                                          lnk =ln A - (\frac{E_{a} }{R}) \frac{1}{T}

We have

                ln k = 42.019 - 15008 * (\frac{1}{300} )

                      k = 0.00033(\frac{dm^{3} }{mole} )^{2} \frac{1}{s}

Hence the rate constant is k = 0.00033(\frac{dm^{3} }{mole} )^{2} \frac{1}{s}    

6 0
3 years ago
When one plate slides under another plate it is called ?
jolli1 [7]
Tectonic plate shifting... 
8 0
3 years ago
Read 2 more answers
What is the formula for copper(ii) phosphate? capitalization and punctuation count!?
iVinArrow [24]
Hello!

The formula for Copper (II) Phosphate is

Cu₃(PO₄)₂

To know how to write this formula we go from left to right. First, Copper (II). It means that the formula has the Cu⁺² ion. Now, Phosphate means that the compound has the PO₄⁻³ ion. Now we combine this two ions, giving to each one the coefficient with the number of the electric charge of the other (e.g. to Cu⁺² we'll give the charge of PO₄⁻³ which is 3 and the result will be Cu₃⁺²). 

The combination gives us the result Cu₃(PO₄)₂

Have a nice day!
4 0
4 years ago
Suggest why sodium and hydrogen ions do not diffuse at the same rate
Troyanec [42]

Answer:

sodium has got ionic bonds that are weak

compared to hydrogen covalent bonds that are strong

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