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3 years ago

What is the formula for copper(ii) phosphate? capitalization and punctuation count!?

1 answer:

4 0

Hello!

The formula for Copper (II) Phosphate is

Cu₃(PO₄)₂

To know how to write this formula we go from left to right. First, Copper (II). It means that the formula has the Cu⁺² ion. Now, Phosphate means that the compound has the PO₄⁻³ ion. Now we combine this two ions, giving to each one the coefficient with the number of the electric charge of the other (e.g. to Cu⁺² we'll give the charge of PO₄⁻³ which is 3 and the result will be Cu₃⁺²).

The combination gives us the result Cu₃(PO₄)₂

Have a nice day!

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Consider the reaction.

Kaylis [27]

Answer:

2.1 x 10^-2

Explanation:

Divide 8.4 x 10^-3 x 8.4 x 10^-3 by 5.82 x 10^-2 and you end up with 2.1 x 10^-2

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3 years ago

In which of the following reactions does a decrease in the volume of the reaction vessel at constant

Black_prince [1.1K]

Answer:

The correct option is: A) 2H₂(g) + O₂(g) → 2H₂O(g)

Explanation:

According to the Le Chatelier's principle, change in the volume of the reaction system causes equilibrium to shift in the direction that reduces the effect of the volume change.

When the volume decreases then the pressure of the reaction vessel increases, then the equilibrium shifts towards the reaction side that produces less number of moles of gas.

A) 2H₂(g) + O₂(g) → 2H₂O(g)

The number of moles of reactant is 3 and number of moles of product is 2.

Therefore, when volume decreases, the equilibrium shifts towards the product side, thereby favoring the formation of products.

B) NO₂(g) + CO(g) → NO(g) + CO₂(g)

The number of moles of reactant and product both is 2.

Therefore, when the volume decreases, the equilibrium does not shift in any direction.

C) H₂(g) + I₂(g) → 2HI(g)

The number of moles of reactant and product both is 2.

Therefore, when the volume decreases, the equilibrium does not shift in any direction.

D) 2O₃(g) → 3O₂(g)

The number of moles of reactant is 2 and number of moles of product is 3.

Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby favoring the formation of reactants.

E) MgCO₃(s) → MgO(s) + CO₂(g)

The number of moles of reactant is 1 and number of moles of product is 2.

Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby favoring the formation of reactants.

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3 years ago

List 4 ways that exercise affects the circulatory system and the respiratory system? Give me a good answer please

KengaRu [80]

<h2>Long term benefits</h2>

Increased heart rate.
Increased breathing rate.
Increase in systolic blood pressure.
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Increased volume of air in the lungs.
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2 years ago

URGENT!!!!!!!!Which reaction takes place in a nuclear fission reactor?

ivolga24 [154]

Answer: The correct answer is Option d.

Explanation:

Nuclear fission reaction is defined as the reaction in which 1 heavier nuclei splits into two or more smaller nuclei.

As, nuclear fission reactors require a large amount of energy to split the nucleus, hence it is bombarded with a particle in order to star the reaction.

In a nuclear reaction, a large fissile atomic nucleus like Uranium-235 $(_{92}^{235}\textrm{U})$ or Plutonium-239 $(_{94}^{239}\textrm{Pu})$ when absorbs a neutron, it undergoes nuclear fission reaction.

Hence, in the given options, uranium-235 is absorbing a neutron. Therefore, the correct answer is Option d.

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2 years ago

Read 2 more answers

The general formula for the alkyne series is: CnH2n+2 CnH2n CnH2n-2 CnHn+2

jeyben [28]

The general formula for alkyne series is CnH2n-2

This is because alkyne is unsaturated hydrocarbon which has one triple bond and has no functional group from homologous series. Alkyne has a general formula of CnH2n-2

An example of an alkyne in ethyne with HC≡CH chemical formula ,

another example is propyne with CH3C≡CH formula

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3 years ago