<span>39a⁶b² and 6a²b³
</span>39a⁶b² =3*13a⁶b² = 3*13a²a⁴b² =(3a²b²)*13a⁴
6a²b³ =2*3*a²b³ =2*3*a² *b*b²=(3a²b²)*2b
so (3a²b²) is the greatest common factor
Answer:
C
Step-by-step explanation:
Answer:
C. a = 7
D. c = -3
Step-by-step explanation:
C. 7(2a + 3) + 21 = 100+ 40
14a + 21 + 21 = 140
14a = 140 - 21 - 21
14a = 98
a = 7
D. 6+ 14 - 12c = 56
20 - 12c = 56
-12c = 56 - 20
-12c = 36
c = - 3
<span>Let x=smaller number
Then x+5=larger number
Now we are told the following:
1/5(x+x+5)=x-5 multiply each side by 5
x+x+5=5x-25 subtract 5x and also 5 from both sides
x+x+5-5-5x=5x-5x-25-5 collect like terms
</span><span>-3x=-30 divide both sides by -3
x=10 smaller number
x+5=10+5=15 larger number
CK
1/5(10+15)=10-5
1/5(25)=10-5
5=5 </span>
