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Mice21 [21]
3 years ago
5

What is the averge of 70 and 93?

Mathematics
2 answers:
ruslelena [56]3 years ago
7 0
The average is 81.5

To find the average, you need to add the numbers together and divide it by 2

70+93= 163

163/2=81.5
pychu [463]3 years ago
3 0
Add 70+93, then divide by the number of numbers, which is 2.
70+90=163
163/2=81.5
Hope this helps!
You might be interested in
Two equivalent ratios for 12/60
Marat540 [252]
If you would like to know two equivalent ratios for 12/60, you can calculate this using the following steps:

12/60 = 12/2 / 60/2 = 6/30
6/30 = 6/2 / 30/2 = 3/15
3/15 = 3/3 / 15/3 = 1/5

The result would be 6/30 or 3/15 or 1/5.
8 0
3 years ago
Read 2 more answers
When solving a 2 step inequality, when do you flip the inequality sign, i keep getting these questions wrong, pls help, i mark b
vaieri [72.5K]
You flip the signs when you are dividing by a negative value.
-2x+3>15
-2x>15-3
-2x>12
x<12/-2
x<-6
Now to test this
Try putting x in the original equation when it is -5.
-2(-5)+3>15
10+3>15
13>15
This is false because our answer says x is less than -6.
Now any value less than -6 will work so let's go with -7.
-2(-7)+3>15
14+3>15
17>15
This result is True.
Hope this helps out!







3 0
3 years ago
2. Find the missing angle x.<br> 155°<br> 60°<br> X
Kryger [21]

Answer:

exterior angle property use ...

the exterior angle of an angle is equal to sum of rest 2 interior angles in a triangle

155 = 60 + x

x = 155 - 60 = 95

8 0
3 years ago
Solve for p.<br><br> p + 36 = 73<br><br> p =
andrew-mc [135]

Answer:

p=37

Step-by-step explanation:

to get p by its self, you would do:

p+36=73

 -36=-36

p=37

3 0
2 years ago
Read 2 more answers
A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

6 0
3 years ago
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