Measured values are verified and go under a series of experiments before being accepted as the norm. Accepted values are unanimously accepted values, seen as the norm by a qualified group of individuals (scientists or the people of the intellectual sphere).
Answer:
The answer to your question is molality = 0.61
Explanation:
Freezing point is the temperature at which a liquid turns into a solid if a solute is added to a solution, the freezing point changes.
Data
Kf = 1.86 °C/m
molality = ?
ΔTc = 1.13°C
Formula
ΔTc = kcm
Solve for m
m = ΔTc/kc
Substitution
m = 1.13 / 1.86
Simplification and result
m = 0.61
Answer:
kJ/mol
Explanation:
Given and known facts
Mass of Benzene 
grams
Mass of water 
grams
Standard heat capacity of water 
J/g∙°C
Change in temperature ΔT 
°C
Heat
Heat released by benzine is - 7.82 kJ
Now, we know that
grams of benzene release 
kJ heat
So, 
g benzine releases
kJ/g
mol C6H6
Heat released
kJ/mol
Assuming that the O2 gas acts like an ideal gas, we find
the following expression to be approximates of the behaviour of this gas:
<span>P V = n R T --->
1</span>
where,
P = pressure exerted by the gas
V = volume occupied
n = number of moles
R = universal gas constant
T = absolute temperature
Further, we assume that the number of moles and the
temperature are constant, hence reducing equation 1 into the form:
<span>P V = k --->
2</span>
where k is a constant. Therefore we can equate two
states:
P1 V1 = P2 V2
Since P1, V1 and V2 are given and we are to look for P2:
25 mL * 2 atm = 100 mL * P2
<span>P2 = 0.5 atm</span>
