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maxonik [38]
3 years ago
8

Help me ASAP! *show work for both* *Brainliest*

Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0
3


Hope I helepd thanks
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What is the product of 1/2x-1/4 and 5^2-2x+6 <br> Show work please need an answer fast
kaheart [24]
1/8 for the first one and second one is 23 times 6

7 0
3 years ago
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Find the area of a parallelogram with bass 15 yards and height 21 2/3yards
r-ruslan [8.4K]
Convert the mixed number <span>21 <span>2/3</span></span><span> into an </span><span>improper fraction.
</span>15⋅<span>65/3

</span><span>Cancel 3 and 15.
</span><span>5⋅65

</span>Multiply 5<span> by </span>65<span> to get </span><span>325.
</span>325

Answer:
325
4 0
3 years ago
Please help and explain with these 2 math questions!!!!!!
Volgvan

1)  -10x+y=4

Now, you should substitute x in every situation.

* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>

<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>

<u />*x=0 => -10*0+y=4... <u>y=4</u>

<u />* x=1 =>  -10*1+y=4... -10+y=4... <u>y=14</u>

<u />* x=2 => -10*2+y=4... -20+y=4... <u>y=24</u>

<u>2)</u> -5x-1=y

For example: x=0

-5*0-1=-1

<u>
</u>



6 0
3 years ago
The function f ( x ) = x ^3 + 2x^2− 5 x − 6 has a root at 2. Name all roots of this function.
Tomtit [17]

sub x=1 into f(x),

remainder= 1^3+2(1)^2-5(1)-6= -8

since remainder≠0, x=1 is not a root of the function

sub x=-1,

remainder = (-1)^3+2(-1)^2-5(-1)-6= 0

by remainder theorem,

x=-1 is a root of f(x)

hence, the correct ans is c

6 0
3 years ago
Find the distance between (4,6) and (-2, -2)
Nataly [62]

Answer:

\displaystyle d = 10

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (4, 6)

Point (-2, -2)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                     \displaystyle d = \sqrt{(-2-4)^2+(-2-6)^2}
  2. Subtract:                                \displaystyle d = \sqrt{(-6)^2+(-8)^2}
  3. Exponents:                            \displaystyle d = \sqrt{36+64}
  4. Add:                                       \displaystyle d = \sqrt{100}
  5. Evaluate:                               \displaystyle d = 10
8 0
3 years ago
Read 2 more answers
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