The child tickets were sold that day is 82.
Given the cost of child admission $6.30 and the cost of adult admission $9.80 and on Wednesday 144 tickets were sold for a total sales of $1124.20.
Let the child tickets are x and adult tickets are y.
On Monday, 144 tickets were sold for a total sales.
x+y=144 ........(1)
Total sales = $1124.20
Need to find the child tickets sold on Wednesday.
Total sales = 6.30x+9.80y
Total sales = $1124.20
So,6.30x+9.80y=1124.20 .......(2)
Find the value of y from equation (1), we get
x+y-x=144-x
y=144-x
Now, we will substitute the value of y in equation (2) to find the value of x, we get
6.30x+9.80(144-x)=1124.20
Apply the distributive property that is a(b+c)=ab+ac, we get
6.30x+9.80×144-9.80x=1124.20
6.30x+1411.2-9.80x=1124.20
Combine the variable terms on left side, we get
1411.2-3.5x=1124.20
subtract 1411.2 from both sides, we get
1411.2-3.5x-1411.2=1124.20-1411.2
-3.5x=-287
Divide both sides with -3.5x, we get
-3.5x/(-3.5)=-287/(-3.5)
x=82
Therefore, 82 child tickets were sold on Wednesday when cost of child admission $6.30 and the cost of adult admission $9.80.
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