Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
Answer:
I believe that the answer is 4.13 weeks
Step-by-step explanation:
Since she already has $52 you can automatically start by doing:
$350 - $52 = $298
Since she works 8 hours a week and earns $9 per hour:
8 hours x $9 = $72
Then, take $298 ÷ $72 = 4.13 or about 4 weeks
I divide 298 by 72 because $72 is how much she will earn per week, and by dividing this number by the total amount that she has left to pay narrows it down to about how long she has to save for.
Hope this helps!!
2 cups of flour x cups of flour
–––––––––––– = –––––––––––––
24 cookies 54 cookies
cross multiply
2*54=24x
24x=108
x=4.5
4.5 cups of flour
Welcome to the factorial world :) Remember the Exclamation Point ( ! ) on the calculator, that is called factorial.
For instance: 1! = 1
2! = 1 x 2
3! = 1 x 2 x 3
and so on
10! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 = 3628800
Crazy enough, 0! is actually equal to 1, try that on your calculator XD