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Katena32 [7]
3 years ago
13

What’s 83/20 as a terminating decimal

Mathematics
1 answer:
gayaneshka [121]3 years ago
4 0

Answer:

4.15

Step-by-step explanation:

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Help me pls i will give brainiest answer
evablogger [386]

Answer:

All graphs tell a story and include a title and labels that describe the data.

Sorry I couldnt find the rest of it.

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The graph shows time and distance traveled for two objects.
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C is the answer for the question
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Mr. and Mrs. Simpson went to the movies. They bought some popcorn for $25.50, two boxes of candy for $18 and two drinks for $14.
Ne4ueva [31]
You add all of those numbers together and get your answer which is 60, so basically like this

25.50 + 14.25 + 18 + 2.25 = 60
4 0
2 years ago
A rectangle. one side is 2x + 7 and the other is x+3
saveliy_v [14]

\large{\green}\fcolorbox{purple}{pink}{\bf{\underline{\red{\color{red}Answer}}}}

6x + 20

Step-by-step explanation:

  • <u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>

Perimeter of rectangle

  • <u>Given</u><u> </u><u>:</u><u>-</u>

Length = 2x + 7

Breadth/width = x + 3

  • <u>Solution</u><u> </u><u>:</u><u>-</u>

<em>We</em><em> </em><em>know</em><em> </em><em>that</em>

<em>\mathfrak {perimeter \: of \: rectangle =2(length + breadth) }</em>

<em>Now</em><em> </em><em>we</em><em> </em><em>will</em><em> </em><em>substitute</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>length</em><em> </em><em>and</em><em> </em><em>breadth</em>

<em>\sf  \longmapsto perimeter = 2 \{(2x + 7) + (x + 3) \} \\  \\  \\  \sf \longmapsto perimeter = 2 \{3x + 10 \} \\  \\  \\  \sf  \longmapsto perimeter = 6x + 20</em>

6 0
1 year ago
Suppose each edge of the cube shown in the figure is 10 inches long. Find the sine and cosine of the angle formed by diagonals D
tatiyna

Check the picture below.

sin(EDG )=\cfrac{\stackrel{opposite}{10}}{\underset{hypotenuse}{10\sqrt{3}}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\implies sin(EDG )=\cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{sin(EDG )=\cfrac{\sqrt{3}}{\sqrt{3^2}}\implies sin(EDG )=\cfrac{\sqrt{3}}{3}} \\\\[-0.35em] ~\dotfill

cos(EDG )=\cfrac{\stackrel{adjacent}{10\sqrt{2}}}{\underset{hypotenuse}{10\sqrt{3}}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\implies cos(EDG )=\cfrac{\sqrt{2}}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}} \\\\\\ \stackrel{\textit{rationalizing the denominator}}{cos(EDG )=\cfrac{\sqrt{6}}{\sqrt{3^2}}\implies cos(EDG )=\cfrac{\sqrt{6}}{3}}

4 0
2 years ago
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