If its the capital letters:
TEIEDIII
i dont really think thats right tho :/
Answer: Our required probability is 2.8%.
Step-by-step explanation:
Since we have given that
Probability of products slit with new blades have rough edges P(X) = 1%
Probability of products slit with blades of average sharpness exhibit roughness P(Y) = 3%
Probability of products slit with worn blades exhibit roughness P(Z) = 5%
Let A be the selected product that exhibit edge roughness.
P(A|X) = 25% = 0.25
P(A|Y) = 60% = 0.60
P(A|Z) = 15% = 0.15
So, the probability of products that exhibit edge roughness is given by
Hence, our required probability is 2.8%.
Answer: 12 is the answer
Step-by-step explanation: Brainliest please
Answer:
14
Step-by-step explanation:
Because 40% of the class is playing games, that means (100-40)% aren't playing, meaning that those 60% haven't finished the assignment.
We find 60% of the total 24 students, and that is .6 * 24 = 14.4
Because you can't have .4 people, the answer rounds (down ) to 14
<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
