Evaluate the expression when a = 10. a/4 + 1/3

1 answer:

7 0

10/4 + 1/3 = 17/6

step 1: reduce the fraction with 2:

5/2 + 1/3

step 2: write all numerators above the common denominator 6:

15 + 2/ 6

step 3: add the numbers:

17/6

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A tangent line and its normal line have a point of tangency to the function f(x) at (x,y). If the slop of the normal line is m=(

alekssr [168]

Answer:

$\displaystyle \\\left(\frac{49}{900},\frac{3761}{900}\right)$ or approximately (0.544, 4.179)

Step-by-step explanation:

A function and its tangent lines intersect when their slopes are the same. Find the x-coordinate when the slope of f(x) is equal to 8/7 by taking the derivative of f(x):

$\displaystyle\\f(x)=\sqrt{x}-x+4\\f'(x)=\frac{1}{2}\cdot\frac{1}{\sqrt{x}}-1=\frac{1}{2\sqrt{x}}-1$

Set $f'(x)$ equal to 8/7 and solve for x:

$\displaystyle \\\frac{1}{2\sqrt{x}}-1=\frac{8}{7},\\x=\frac{49}{900}$

Therefore, $f(x)$ will intersect at a point of tangency with a line of slope 8/7 at x=49/900. Plug in x=49/900 into $f(x)$ to get the y-coordinate:

$\displaystyle\\y=\sqrt{x}-x+4 \vert_{x=49/900}=\frac{3761}{900}$

⇒Answer: (49/900, 3761/900) or approximately (0.544, 4.179)

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2 years ago

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Korvikt [17]

Answer: $0.9999$

Step-by-step explanation:

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3 years ago

Use the graph of the derivative of f to locate the critical points x0 at which f has neither a local maximum nor a local minimum

jok3333 [9.3K]

<span>Critical points are where the derivative is 0, i.e. where it crosses the x - axis

The Critical points lies where the derivative is 0, while it crosses the x-axis, SO, in this case the choice 3 looks like best answer for this.
</span>

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Answer:

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Step-by-step explanation:

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