We can write a proportion to resemble the problem;
AE/ED = AB/BC
AE = 9
ED = 6
AB = x
BC = 10
Substitute with the given values.
9/6 = x/10
9/6 * 10 = x/10 * 10
90/6 = x
15 = x
Therefore, the answer is 15.
Best of Luck!
Answer:
B. 4
Step-by-step explanation:
The maximum number of teams the teacher can divide the class into is 4. I got it right on ED2020.
Answer:
1. 136.3/53% = 257.16981...
2. 99/231.2 = 0.4282
3. 853.2/51% = 1672.94117....
4. 439.7/0.56 = 785.17857
5. 496.1/0.92 = 539.23913
6. 0.32 x 238.3 = 76.256
7. 99/376.3 = 0.26308
8. 0.08 x 493.7 = 39.496
Step-by-step explanation:
Good luck
Answer:
b hours
Step-by-step explanation:
100 minus the 10 on the jacket equals 90. 90 divided by 15 is 6
