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natta225 [31]
2 years ago
5

Adam, Beth, and Carly walked a total of 10 miles collectively. Beth walked twice as far as Adam, and she walked a half a mile fu

rther than Carly. If a = number of miles Adam walks, b = number of miles Beth walks, and c = number of miles Carly walks, which equation is NOT true for this situation?
A) b = 2a
B) b = c + 0.5
C) 3a + c = 10
D) a + 2c = 10.5
Mathematics
2 answers:
bearhunter [10]2 years ago
8 0
D) a+2c=10.5

Since b=c+\frac{1}{2}
a+b+c=10
a+(c+1/2)+c=10
a+2c+1/2=10
a+2c=9.5
Basile [38]2 years ago
8 0

Answer: Option 'D' is not correct.

Step-by-step explanation:

Since we have given that

Total distance walked by Adam , Beth, and Carly = 10 miles

Let number of miles Adam walks be a

Let number of miles Beth walks be b

Let number of miles Carly walks be c

According to question,

<u>Beth walked twice as far as Adam </u>

So, the equation will be

b=2a

Thus, Option 'A' is satisfied.

<u>Now, Beth walked a half a mile further than Carly.</u>

So, the equation will be

b=c+0.5

Thus, Option 'B' is correct.

Now, we substitute the first equation, then we get

a+b+c=10\\a+2a+c=10\\3a+c=10

Thus, Option 'C' is correct.

<u>The only incorrect equation is Option 'D' .</u>


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According to the condition,



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