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2 years ago

Write your question here (Keep it simple and clear to get the best answer) simplify (3x-4y)(5x+2y)-(x+y)

Mathematics

2 answers:

Inessa05 [86]2 years ago

4 0

Answer:

hope it helped

have a good day

Komok [63]2 years ago

3 0

Answer:

15x^2−14xy−8y^2−x−y

Step-by-step explanation:

Combine like units.

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Write the equation for the graphed function. I worked out y = 5 - 4 (x + 4)^2 but that isn't right. Any help would be appreciate

alexira [117]

Vertex form for a parabola with vertex (p,q) is

$y = a(x-p)^2 + q$

We have (p,q)=(-4,5) and another point (-3,2) so we can solve for a:

$2 = a(-3 - -4)^2 + 5$

$2 = a + 5$

$a = -3$

Putting it together,

Answer: $y = -3(x + 4)^2 + 5$

We could multiply that out if we like but I won't bother.

5 0

2 years ago

F(x) = x2 + 9, g(x) = *square root of* x + 8, find g(f(x))

ICE Princess25 [194]

Answer:

g(f(x)) = √(x^2 +17)

Step-by-step explanation:

For ...

f(x) = x^2 +9

g(x) = √(x +8)

The definition of g(f(x)) is ...

g(f(x)) = g(x^2 +9) = √((x^2 +9) +8)

g(f(x)) = √(x^2 +17)

6 0

2 years ago

Please help me! WILL MARK BRAINLIEST. Thanks!

galben [10]

Answer:

For the first table: (0, 10) (1, 15) (2, 20) (3, 25) (4, 30)

For the second table: (-2, 1.04) (-1, 1.2) (0, 2) (1, 6) (2, 26)

For the third table: (-2, 10) (-1, 0) (-1/2, -5/4) (1, 10)

Step-by-step explanation:

5 0

2 years ago

sue stacked one box onto another. the bottom had the height of 2 1/3 feet and the top box had the height of 3 2/3 feet. how tall

Scilla [17]

Height of bottom box : - $2 \frac{1}{3} => 7/3$
Height of top box : - $3 \frac{2}{3} => 11/3$

Thus, height of two boxes =

$\frac{7}{3} + \frac{11}{3} = \frac{18}{3} => 6ft$

Happy to help chodini!

3 0

2 years ago

Read 2 more answers

Write and then solve for y = f(x) the differential equation for the statement: "The rate of change of y with respect to x is inv

vazorg [7]

The statement "The rate of change of y with respect to x is inversely proportional to y^4" can be written mathematically as dy/dx = k/y^4

To solve the differential equation, we use variable saparable method.
y^4 dy = kdx
Integrating both sides gives,
y^5 / 5 = kx + A
y^5 = 5kx + 5A = Bx + C; where B = 5k and C = 5A
$y= \sqrt[5]{Bx+C}$

7 0

2 years ago