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3 years ago

Given the following absolute value function sketch the graph of the function and find the domain and range. ƒ(x) = |x + 3| - 1

Mathematics

2 answers:

yuradex [85]3 years ago

5 0

Answer:

The domain is all real numbers

The range is all real numbers greater than or equal to $-1$

Step-by-step explanation:

we have

$f\left(x\right)=\left|x+3\right|-1$

we know that

Using a graphing tool

see the attached figure

The vertex of the function is the point $(-3,-1)$

The domain of the function is the interval-------> (-∞,∞)

All real numbers

The range of the function is the interval-------> [-1,∞)

All real numbers greater than or equal to $-1$

julsineya [31]3 years ago

4 0

I attached a graph of the function for you to look at. For domain and range use what you know, domain is how far it can stretch from left to right, and the range of the function is how far it can go from bottom to top.

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Help asap!!!!!!!!!! Properties of exponents Simplify

maksim [4K]

Answer:

C) $4a^{6}b$

Step-by-step explanation:

$\frac{(4b^{3} 3a^{4}b^{2})}{3a^{-2} b^{4}}$ Copy the original equation

$\frac{12a^{6}b^{5}}{3b^{4} }$ Combine like terms

$\frac{12a^{6}b}{3}$ Simplify the b, then divide by 3

$4a^{6}b$

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4 years ago

Write a polynomial function $f$ of least degree that has rational coefficients, a leading coefficient of 1, and the given zeros.

olganol [36]

Answer:

$f(x) = x^{3} + 4x^{2} -7x^{} -10^{}$

Step-by-step explanation:

The zeros of the polynomial function are given us as -5,-1,2

If the zeros of a polynomial function are α,β,ω, the polynomial function can be obtained using the expression below:

f(x) = (x - α)(x - β)(x - ω)

where α = -5, β = -1, and ω = 2

$f(x)=(x-(-5) )(x -(-1))(x - 2) = (x+5)(x+1)(x-2)\\\\f(x)=(x+5)(x^{2} -2x + x -2) = (x+5)(x^{2} -x-2)\\\\f(x)=x(x^{2} -x-2)+5(x^{2} -x-2)\\\\f(x)= x^{3} - x^{2} -2x + 5x^{2} - 5x - 10\\\\f(x)= x^{3} + 4x^{2} -7x - 10$