Answer:
because the orange is unripe
pyramidal, if you have a molecule kit, i would strongly recommend watching a video of someone using a kit explaining the different shapes and following along. It helps a lot!
Answer:

Explanation:
<u><em>Given :</em></u>
Mass in grams = m = 42 g
Molar Mass = M = 12
<u><em>Required:</em></u>
No. of moles = n = ?
<u><em>Formula :</em></u>
m = m / M
<u><em>Solution:</em></u>
n = 42 / 12
n = 3.5 moles
The answer would be Rutherford inferred the existence of a dense, positively charged nucleus.
Answer: 2.75%
Explanation:
![pH=-log [H+]](https://tex.z-dn.net/?f=pH%3D-log%20%5BH%2B%5D)
![3.26 = -log [H+]](https://tex.z-dn.net/?f=3.26%20%3D%20-log%20%5BH%2B%5D)
![[H+] = 5.495\times 10^{-4} M](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%205.495%5Ctimes%2010%5E%7B-4%7D%20M)

initial 0.020 0 0
eqm 0.020 -x x x
![K_a=\frac{[H+][A-]}{[HA]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D)
![K_a=\frac{[x][x]}{[0.020-x]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.020-x%5D%7D)

![K_a=\frac{[5.495\times 10^{-4}]^2}{[0.020-5.495\times 10^{-4}]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5B5.495%5Ctimes%2010%5E%7B-4%7D%5D%5E2%7D%7B%5B0.020-5.495%5Ctimes%2010%5E%7B-4%7D%5D%7D)

percent dissociation = ![\frac{[H^+_eqm]}{[Acid_{initial}]}\times 100](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%2B_eqm%5D%7D%7B%5BAcid_%7Binitial%7D%5D%7D%5Ctimes%20100)
percent dissociation=
Thus percent dissociation= 2.75 %