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Butoxors [25]
3 years ago
6

How many atoms of aluminum (Al) are in 6.4 mol of aluminum

Chemistry
1 answer:
stepan [7]3 years ago
6 0

Answer:

How many atoms are in 6.2 moles of aluminum? I mol = 6.02X1023 atoms so 6.2 mol = 6.2x (6.02x1025) = 3.73 x1024 atoms of Aluminum

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Carbon is stored in the ocean
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3 years ago
A Student Formulated A Hypothesis That Cotton Will Grow Larger Bolls ( Pods ) If Magnesium Is Added To The Soil. The Student Has
Sati [7]
Hypothesis is a smart guess that you make on the result of your experiment. You make this even before doing the experiment through inferential analysis. If the hypothesis you made was that, cotton will grow larger balls, then in the experiment, you should measure the cotton boll's size. The size should be in terms of diameter. So, the answer is b.
4 0
3 years ago
Which of the following are always larger than the neutral atoms from which they are formed?
Anuta_ua [19.1K]

Answer:

A) Cations

Explanation:

a) Cations have a positive charge and are larger than their neutral counterparts!

b) Anions have a negative charge and are smaller than their neutral counterparts

c) Metals can have either a positive or negative charge making it either a cation or an anion

d) Carbon is an element and it can have a charge anywhere from +4 to -4

A good way to remember that cations are positive is to think that CATions are always PAWSitive! ^-^

3 0
3 years ago
A smaple of 1cm cuvette gives an absorbance reading of 0.558. if they absorptivity for this sample is 15000l/(mol.cm), what is t
Mazyrski [523]
To solve this problem, we use Beer's Law: A= ε.l.c
A is the absorbance- 0,558
<span>ε is</span> the molar absorptivity- is <span>15000 </span><span><span>L⋅mol-1</span><span>cm-1</span></span>
<span>l is </span>the length of the cuvette- 1 cm
<span>c is</span> the molar concentration

Applying the formula,
0,558= 15000 x 1 x c
0,558/15000= c
c= <span>3.72×<span>10⁻⁵ </span> <span>mol⋅L<span>⁻¹</span></span></span>
<span />
3 0
3 years ago
Define the term diffusion
maw [93]

Answer:

Spreading, like dispersing.

Explanation:

7 0
3 years ago
Read 2 more answers
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