Answer:
Remain unchanged.
Explanation:
The total number of moles of liquid remain unchanged as the some moles of species B are added to the system because specie B that is added in the liquid phase is again restored after addition. If the specie B did not restored after addition to the liquid phase so the total number of moles increases in the liquid phase so that's why we can say that the liquid phase remain unchanged.
Answer:
Therefore it takes 8.0 mins for it to decrease to 0.085 M
Explanation:
First order reaction: The rate of reaction is proportional to the concentration of reactant of power one is called first order reaction.
A→ product
Let the concentration of A = [A]
![\textrm{rate of reaction}=-\frac{d[A]}{dt} =k[A]](https://tex.z-dn.net/?f=%5Ctextrm%7Brate%20of%20reaction%7D%3D-%5Cfrac%7Bd%5BA%5D%7D%7Bdt%7D%20%3Dk%5BA%5D)
![k=\frac{2.303}{t} log\frac{[A_0]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%20log%5Cfrac%7B%5BA_0%5D%7D%7B%5BA%5D%7D)
[A₀] = initial concentration
[A]= final concentration
t= time
k= rate constant
Half life: Half life is time to reduce the concentration of reactant of its half.

Here 


To find the time takes for it to decrease to 0.085 we use the below equation
![k=\frac{2.303}{t} log\frac{[A_0]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%20log%5Cfrac%7B%5BA_0%5D%7D%7B%5BA%5D%7D)
![\Rightarrow t=\frac{2.303}{k} log\frac{[A_0]}{[A]}](https://tex.z-dn.net/?f=%5CRightarrow%20t%3D%5Cfrac%7B2.303%7D%7Bk%7D%20log%5Cfrac%7B%5BA_0%5D%7D%7B%5BA%5D%7D)
Here ,
, [A₀] = 0.13 m and [ A] = 0.085 M


Therefore it takes 8.0 mins for it to decrease to 0.085 M
opinion and belief mean a judgment that someone thinks is true. ... belief is used if the judgment is certain and firm in a person's own mind without regard to the amount or kind of evidence.
well one thing that’s unique about water is the fact that it’s dipole, meaning that water has both a positive side and a negative side.
Answer:
41.4 g
Explanation:
2Na(s) + 2H2O (l) ----> 2NaOH ( aq) + H2 (g)
According to the above balnced chemical equation the ratio between moles of H2 gas formed to moles of Na used up is 1:2
Molar mass ( Mass of 1 mol) Of H2 gas is 2 gmol-1
So in 1.8 g of H2 0.9 mol should be present
Therefore no. of moles of Na used should be 2× 0.9 = 1.8 moles
Molar mass of Na= 23 gmol-1
So mass of 1.8 mol of Na = 1.8× 23 g = 41.4g